PSLE Maths 2012

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 Post subject: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 8:53 am 
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KiasuGrandMaster
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Will it be easy or difficult? Verdict will be out in 3 hours' time.


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 9:26 am 
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KiasuGrandMaster
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Paper 1 (40 marks, no calculator) would have been completed by now. Is it easy?


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 9:34 am 
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OrangeBelt
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James Ang wrote:
Paper 1 (40 marks, no calculator) would have been completed by now. Is it easy?


DD just called. She said is quite easy this year. If easy, that means mean mark will go up. It w b hard to score high point.


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 11:00 am 
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KiasuGrandMaster
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That's great. 1 more hour to go.


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 11:45 am 
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GreenBelt
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James Ang wrote:
That's great. 1 more hour to go.


Paper 1 was easy, except one tricky qn no 29.


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 12:37 pm 
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KiasuNewbie
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Paper 2 was quite challenging


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 12:48 pm 
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KiasuNewbie
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question 29 answer is 28. right
from what my son says the method is as follows
110 minus 1 as the last man is an extra out of the group
then use 109 divided by 4 which gives u 27 r1 as in a group there can be 3 women and 1 men
the remainder of 1 means that in one of the group they have 4 women
then add 1 to 27 as there is still a man at the back
and my son also said that those ppl who put 44 has double counted the man
making it: m w w w m m w w w m m
thus it will have no women in betwwen some of the men


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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 12:54 pm 
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YellowBelt
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How on earth do you do the last question for paper 2?


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 Post subject: .
PostPosted: Fri Sep 28, 2012 12:54 pm 
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YellowBelt
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.


Last edited by sharmila on Fri Sep 28, 2012 1:07 pm, edited 2 times in total.

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 Post subject: Re: PSLE Maths 2012
PostPosted: Fri Sep 28, 2012 12:58 pm 
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GreenBelt
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wargame123 wrote:
question 29 answer is 28. right
from what my son says the method is as follows
110 minus 1 as the last man is an extra out of the group
then use 109 divided by 4 which gives u 27 r1 as in a group there can be 3 women and 1 men
the remainder of 1 means that in one of the group they have 4 women
then add 1 to 27 as there is still a man at the back
and my son also said that those ppl who put 44 has double counted the man
making it: m w w w m m w w w m m
thus it will have no women in betwwen some of the men

My dd ans also 28 :sweat:


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