## Q&A - P5 Math (Page 174)

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 Post subject: Re: Q&A - P5 MathPosted: Thu Jan 31, 2013 7:43 pm
 OrangeBelt

Joined: Mon Jan 09, 2012 6:07 am
Posts: 73
tianzhu wrote:
elisammom wrote:
Hi pls help. This is the 2011 CA1 Nanhua paper

TIA

Hi
You may use "Listing"

Total number of students for A, C,D and E ------- 77

Find multiples of 5 and 7 after 77

Multiples of 5 ------ 80,85,90,95

Multiples of 5 + 1 ------ 81,86,91,96

Multiples of 7 ------ 84, 91

Multiples of 7 + 5 ------ 89, 96

The common number is 96

Least number of students in B ------- 96-77 ------- 19

Hope this helps

Best wishes

Very clear! Thanks a lot!

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 Post subject: Re: Q&A - P5 MathPosted: Thu Jan 31, 2013 7:49 pm
 KiasuGrandMaster

Joined: Wed Mar 09, 2011 11:49 pm
Posts: 2346
Trina wrote:

There are 40 pupils in a class. Each boy donated \$3 and each girl donated \$2. The boys donated \$30 more than the girls.
How many boys are there?
How many girls are there?

Thanks!

Assume all boys donated, total amount --> 40 x \$3 = \$120
\$120 - \$30 = \$90 --- excess amount to be reduced by girls' donation
Number of girls = \$90/(\$3+\$2) = 18
Number of boys = 40-18 = 22

cheers.

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 Post subject: Re: Q&A - P5 MathPosted: Thu Jan 31, 2013 8:05 pm
 GreenBelt

Joined: Mon Nov 30, 2009 1:08 pm
Posts: 188
MathIzzzFun wrote:
Trina wrote:

There are 40 pupils in a class. Each boy donated \$3 and each girl donated \$2. The boys donated \$30 more than the girls.
How many boys are there?
How many girls are there?

Thanks!

Assume all boys donated, total amount --> 40 x \$3 = \$120
\$120 - \$30 = \$90 --- excess amount to be reduced by girls' donation
Number of girls = \$90/(\$3+\$2) = 18
Number of boys = 40-18 = 22

cheers.

Thanks but still dont get it.. Can provide narration? Thanks

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 Post subject: Re: Q&A - P5 MathPosted: Thu Jan 31, 2013 9:01 pm
 BlueBelt

Joined: Sat Mar 14, 2009 11:02 pm
Posts: 243
Luke had \$140 and Issac had \$92 at first. After they spent an equal amount of money, Luke had 4 times as much money as Isaac. How much did each of them spend?
(not sure if this has been asked before, pls refer me to correct page. Thanks!)

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 Post subject: Re: Q&A - P5 MathPosted: Thu Jan 31, 2013 9:10 pm
 KiasuGrandMaster

Joined: Mon Jul 26, 2010 4:01 pm
Posts: 1644
ttyh wrote:
Luke had \$140 and Issac had \$92 at first. After they spent an equal amount of money, Luke had 4 times as much money as Isaac. How much did each of them spend?
(not sure if this has been asked before, pls refer me to correct page. Thanks!)

3 units -> \$140 - \$92 = \$48
1 unit -> \$48 / 3 = \$16

\$92 - \$16 = \$76

Each of them spent \$76

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 Post subject: Re: P5 Onsponge Conquer Problem Sums Answer keyPosted: Thu Jan 31, 2013 9:25 pm
 GreenBelt

Joined: Thu Jan 31, 2013 9:01 pm
Posts: 120
If you need the whole answer key, I don't think I could help. But if you just need some answers from the answer key, then you can go to the website. http://www.onsponge.com/shop/online-solutions.html
Hope I helped

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 Post subject: Re: Q&A - P5 MathPosted: Thu Jan 31, 2013 11:55 pm
 OrangeBelt

Joined: Wed Nov 19, 2008 10:44 pm
Posts: 54
Serene, Fabian and Eileen shared their prize money of \$4100 among themselves. Twice of Serene's share was equal to 5 times of Fabian's share. 4 times of Serene's share was also equal to 3 times of Eileen's share. Calculate Serene's share.

Help ...... please. How should the answers be presented and is this really a P5 appropriate question?

Thank you very much.

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 Post subject: Re: Q&A - P5 MathPosted: Fri Feb 01, 2013 2:29 am
 KiasuGrandMaster

Joined: Mon Oct 12, 2009 5:48 pm
Posts: 1409
Oracle wrote:
Serene, Fabian and Eileen shared their prize money of \$4100 among themselves. Twice of Serene's share was equal to 5 times of Fabian's share. 4 times of Serene's share was also equal to 3 times of Eileen's share. Calculate Serene's share.

Help ...... please. How should the answers be presented and is this really a P5 appropriate question?

Thank you very much.

Hi Oracle,

One Possible Solution:

Twice of Serene's share was equal to 5 times of Fabian's share.
This means that ratio of Serene's share to Fabian's share is 5:2
(Just interchange the 2 numbers)

4 times of Serene's share was also equal to 3 times of Eileen's share.
This means that ratio of Serene's share to Eileen's share is 3:4
(Just interchange the 2 numbers)

Ratio of Serene's share to Fabian's share is 5:2
Ratio of Serene's share to Eileen's share is 3:4

Ratio of Serene's share to Fabian's share to Eileen's share is 15:6:20

15 + 6 + 20 = 41 units
41 units = \$4100

Can you work from here?

Cheers

speedmaths.com

.

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 Post subject: Re: Q&A - P5 MathPosted: Fri Feb 01, 2013 6:16 am
 KiasuGrandMaster

Joined: Wed Mar 09, 2011 11:49 pm
Posts: 2346
Oracle wrote:
Serene, Fabian and Eileen shared their prize money of \$4100 among themselves. Twice of Serene's share was equal to 5 times of Fabian's share. 4 times of Serene's share was also equal to 3 times of Eileen's share. Calculate Serene's share.

Help ...... please. How should the answers be presented and is this really a P5 appropriate question?

Thank you very much.

cheers.

Top

 Post subject: Re: Q&A - P5 MathPosted: Fri Feb 01, 2013 9:53 am
 KiasuGrandMaster

Joined: Wed Mar 09, 2011 11:49 pm
Posts: 2346
Trina wrote:
MathIzzzFun wrote:
Trina wrote:

There are 40 pupils in a class. Each boy donated \$3 and each girl donated \$2. The boys donated \$30 more than the girls.
How many boys are there?
How many girls are there?

Thanks!

Assume all boys donated, total amount --> 40 x \$3 = \$120
\$120 - \$30 = \$90 --- excess amount to be reduced by girls' donation
Number of girls = \$90/(\$3+\$2) = 18
Number of boys = 40-18 = 22

cheers.

Thanks but still dont get it.. Can provide narration? Thanks

cheers.

Top

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