The Ivan/Henry qn is similar to Q17 in PSLE 2015 paper.

But it somehow still created a stir last year

ksraja69 wrote:Anyone knows when SMO first round results will be out?

http://sms.math.nus.edu.sg/Default.aspx

Click on the respective section to see the shortlist for R2

cheers.

Can anyone help me with this question? Thank you http://i.imgur.com/jQl35Bxl.jpg At point D, angle ADC (90°) + angle ADC (reflex) = 360° In quadrilateral BCDA, angle DCB + angle CBA + angle BAD + angle ADC (reflex) = 360° ∴ angle DCB + angle CBA + angle BAD =90° angle BAD = 90° - 22° - 41° = 27° ch...

KSP2013777 wrote:I know OB is 15 cm, but what is OQ?

OC = (15-r) cm
Sin (angle COQ) = sin 30° = 1/2

Can continue ?

cheers.

KSP2013777 wrote:My teacher is giving us revision paper. I cannot do this question. Can somebody b pls help?


Thank you

Use right-angle triangle OCQ. Angle COQ= 30°

I believe you can sort this out.

cheers.

http://i57.tinypic.com/54xc47.jpg Find the number of cubes per column on the 10cm x 10cm for 2 cm cubes, one column hold 5 X 5 = 25 cubes For 1 cm cubes, one column hods 10 X 10 = 100 cubes Let the number of columns for 2cm cube be "u" and 1cm cube be "p" 25u + 100p = 700 ---(1) The number of colum...

2015 SMO results @
http://sms.math.nus.edu.sg/competitions/SMO2015.aspx


cheers.

...No, can't do... No worries... you will not get such question in psle...such questions can solved easily using the difference of squares algebraic identity which is taught in sec 1 maths and primary MO.... with all the MO competitions and GATs done with now, concentrate on your psle prep, you can...

ebabe wrote:Thanks! What about these others 2 question?

cheers.

[quote="leo_mums"]

How many cubes are there in Pattern 10?[/quote］

Note that the hollowed space is also a cube.
Pattern 1 → 2³ -1³ = 7
Pattern 2 → 3³-2³ = 19
Pattern 3 → 4³ - 3³= 37
So,
Pattern 10 → 11³ - 10³ =331

cheers.