What is the sum of the coefficients of
( [3x  3x^2 +1]^744 ) x ( [ 3x + 3x^2 +1]^745 ) ??
COEFFICIENTS
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MathsLover123  KiasuNewbie
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Re: COEFFICIENTS
by atutor2001 » Sat Oct 22, 2011 3:08 pm
MathsLover123 wrote:What is the sum of the coefficients of
( [3x  3x^2 +1]^744 ) x ( [ 3x + 3x^2 +1]^745 ) ??
Do you mean : [3x  3x^(2 +1)]^744 ) x [ 3x + 3x^(2 +1)]^745
I think the answer is 0.

atutor2001  KiasuGrandMaster
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HeSheMe  OrangeBelt
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Re: COEFFICIENTS
by warriortemujin » Sun Oct 23, 2011 10:09 am
the ans is 744 X 745 x 3 = 1662840
You need to factorise the Q before getting the coefficient.
Where did u get such weird Q?
You need to factorise the Q before getting the coefficient.
Where did u get such weird Q?

warriortemujin  OrangeBelt
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Re: COEFFICIENTS
by CoffeeCat » Sun Nov 13, 2011 7:16 pm
MathsLover123 wrote:What is the sum of the coefficients of
( [3x  3x^2 +1]^744 ) x ( [ 3x + 3x^2 +1]^745 ) ??
This is a trick question.
If you want the sum of the coefficients in any polynomial, simply substitute x=1 into the polynomial and evaluate.
Hence when you substitute 1 above, you get 1^744 times 1^745 = 1.

CoffeeCat  BrownBelt
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