HCF = 12 = 2^2 x 3marstolive wrote:can anyone show me the solution for this question? C:

The HCF and LCM of two numbers, 12 and 5040 respectively. If one of the numbers is 144, find the other number.

Thanks

LCM = 5040 = 2^4 x 3^2 x 5 x 7

One of the number = 144 = 2^4 x 3^2

So, the other number must have 2^2 x 3 x 5 x 7 = 420