### Re: Lower Secondary Mathematics

Posted:

**Mon Apr 11, 2016 9:34 pm** can anyone please help me with this question.thank you in advance

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Posted: **Mon Apr 11, 2016 9:34 pm**

can anyone please help me with this question.thank you in advance

Posted: **Mon Apr 11, 2016 9:39 pm**

-can you please help with question also. Advanced thank you friends

Posted: **Tue Apr 19, 2016 8:32 pm**

Sruthi wrote: can anyone please help me with this question.thank you in advance

Posted: **Wed Apr 20, 2016 4:39 pm**

Can anyone help me with this question.

1. The sine of an angle is 0.7420. Give two possible values for the angle in degrees.

Answer: ______________ or ______________

1. The sine of an angle is 0.7420. Give two possible values for the angle in degrees.

Answer: ______________ or ______________

Posted: **Thu Apr 21, 2016 9:56 pm**

sin (angle) = positive, when 0 < angle < 180questionable_i wrote:Can anyone help me with this question.

1. The sine of an angle is 0.7420. Give two possible values for the angle in degrees.

Answer: ______________ or ______________

sin (angle) = negative, when 180 < angle < 360

Since sin (angle) = 0.7420 -> positive

Both angles must be between 0 to 180.

sin^(-1) 0.7420 = 47.9 deg (first ans)

180 deg - 47.9 deg = 132.1 deg (second ans)

Posted: **Sun May 01, 2016 4:05 pm**

Kindly help with the following qn, thanks.

Without drawing the graphs, explain why the simultaneous equations

y = -2x + 5

y = 2x - 33

have no solution

Without drawing the graphs, explain why the simultaneous equations

y = -2x + 5

y = 2x - 33

have no solution

Posted: **Sun May 01, 2016 4:28 pm**

Hi, is there any typo error in the question?tankee wrote:Kindly help with the following qn, thanks.

Without drawing the graphs, explain why the simultaneous equations

y = -2x + 5

y = 2x - 33

have no solution

I am able to find the solution, which is x= 9.5 and y=-14.

If the question was to solve

y = 2x + 5

y = 2x - 33

or

y = -2x + 5

y = -2x - 33

then there is no solution

working:

sub. y = 2x+5 into the second equation,

2x+5=2x-33

5=-33 （Not a valid equation)

so no solution.

Please us know if you need further help, the tutors in our centre (who are IP/GEP/RGS/NYGH/ACJC teachers) are able to help you.

Posted: **Sun May 01, 2016 10:14 pm**

Need help with the following questions:-

1) 10f2 - 15f = 0

17g + 45

2) g2 + ----------- = 5

2

Not sure how to place the superscript of square thus f2 and g2.

Question 2 is truncated.

Anyone can tell me how to upload the in pic? Cos has reduced size many times and change from bmp to jpg and etc still cant post.....

1) 10f2 - 15f = 0

17g + 45

2) g2 + ----------- = 5

2

Not sure how to place the superscript of square thus f2 and g2.

Question 2 is truncated.

Anyone can tell me how to upload the in pic? Cos has reduced size many times and change from bmp to jpg and etc still cant post.....

Posted: **Sun May 01, 2016 11:26 pm**

Future Academy wrote:Hi, is there any typo error in the question?tankee wrote:Kindly help with the following qn, thanks.

Without drawing the graphs, explain why the simultaneous equations

y = -2x + 5

y = 2x - 33

have no solution

I am able to find the solution, which is x= 9.5 and y=-14.

......

likewise. But since it has been a while, I thought better seek help to be sure just in case it isn't a typo.

thanks.

Posted: **Tue May 03, 2016 9:03 am**

A quick sketch of the graph will show that there is a solution.tankee wrote:Future Academy wrote:Hi, is there any typo error in the question?tankee wrote:Kindly help with the following qn, thanks.

Without drawing the graphs, explain why the simultaneous equations

y = -2x + 5

y = 2x - 33

have no solution

I am able to find the solution, which is x= 9.5 and y=-14.

......

likewise. But since it has been a while, I thought better seek help to be sure just in case it isn't a typo.

thanks.

I believe that it's a typo, and it probably is on either of the gradient/x-coefficient of the 2 equations.

The explanation should be because the gradient of the lines are the same (-2 OR 2; unable to determine due to typo), that means the 2 equations are parallel to each other, and therefore will never meet each other. => no solutions.