### Re: O-Level Additional Math

Posted:

**Sun Apr 03, 2016 5:19 pm**anyone can help to solve this question? Thank you!

<a href=\"http://www.kiasuparents.com\">KiasuParents.com</a> Forum

https://www.kiasuparents.com:443/kiasu/forum/

https://www.kiasuparents.com:443/kiasu/forum/viewtopic.php?f=29&t=8315

Page **177** of **181**

Posted: **Sun Apr 03, 2016 5:19 pm**

anyone can help to solve this question? Thank you!

Posted: **Sun Apr 03, 2016 6:34 pm**

Give you a guide to start.Angel88 wrote:anyone can help to solve this question? Thank you!

Move one item to the right.

Take lg both side.

Use power law to bring the power down.

Expand and you will be able to group the lg x together and solve.

Try it

Posted: **Sun Apr 03, 2016 6:44 pm**

HI,KSP2013777 wrote:Can somebody pls help me with this question?

Thank you.

Firstly you have to read carefully. Qn is not asking for stationary point of CURVE !

It is asking for the stationary value for the GRADIENT FUNCTION.

Solution :

So you need to differentiate the GRADIENT, then equate it to zero for stationary value

Try it, should be ok now

Posted: **Mon Apr 04, 2016 10:07 pm**

Yes, thank you, Eddow. Got the answer now.

Can you help me with another one.

My ans is e^(3/2), but ans key is 1/e^(1/2). Pls help. Tks

Can you help me with another one.

My ans is e^(3/2), but ans key is 1/e^(1/2). Pls help. Tks

Posted: **Tue Apr 05, 2016 4:05 am**

Hello. I think you might have made a mistake in the differentiation.KSP2013777 wrote:Yes, thank you, Eddow. Got the answer now.

Can you help me with another one.

My ans is e^(3/2), but ans key is 1/e^(1/2). Pls help. Tks

Anyways I suggest you try to simplify the expression (ln part) before differentiating. It will make the differentiation less tedious.

Solution: http://imgur.com/7viZpYS

Posted: **Tue Apr 05, 2016 7:53 pm**

Hi, can anyone help to explain these 2 questions?Thank you. Sorry the upload pic is not up to standard.

Posted: **Wed Apr 06, 2016 10:42 pm**

happyheart wrote: Hi, can anyone help to explain these 2 questions?Thank you. Sorry the upload pic is not up to standard.

Posted: **Sat Apr 16, 2016 8:22 pm**

Can anyone please help me with these questions,

1. 9^y+5(3^y-10)=0

2. 3^2x=16-2(3^x+1)

3. 2^2x=2^x+1+15

Thank you

1. 9^y+5(3^y-10)=0

2. 3^2x=16-2(3^x+1)

3. 2^2x=2^x+1+15

Thank you

Posted: **Sat Apr 16, 2016 11:56 pm**

A rough guide... Use suitable substitution for all the Qn.questionable_i wrote:Can anyone please help me with these questions,

1. 9^y+5(3^y-10)=0

2. 3^2x=16-2(3^x+1)

3. 2^2x=2^x+1+15

Thank you

1. Let u = 3^y

2. Let u = 3^x

3. Let u = 2^x

Then you can carry on solving using quadratic equation.

Try

Posted: **Tue Apr 19, 2016 7:40 pm**

Thank you so much.Eddow wrote:A rough guide... Use suitable substitution for all the Qn.questionable_i wrote:Can anyone please help me with these questions,

1. 9^y+5(3^y-10)=0

2. 3^2x=16-2(3^x+1)

3. 2^2x=2^x+1+15

Thank you

1. Let u = 3^y

2. Let u = 3^x

3. Let u = 2^x

Then you can carry on solving using quadratic equation.

Try