PSLE marks the graduation of Primary school students and their entry into Secondary schools as teenagers. Discuss all issues about Secondary schooling here.
mathtuition88
BlackBelt Posts: 901
Joined: Thu Apr 25,
Total Likes:16

### Re: Secondary School Mathematics

the above method is very nice. mathtuition88
BlackBelt Posts: 901
Joined: Thu Apr 25,
Total Likes:16

### Expansion and Factorisation, HCI IP Sec 2 Revision Pack

Does your child need practice on Expansion and Factorisation, especially the more challenging questions? It is a key technique that needs to be honed for the O Levels.

Practice Hwa Chong Institution Expansion and Factorisation (Sec 2, IP) here.

http://mathtuition88.wordpress.com/2013 ... orisation/

PiggyLalala
KiasuGrandMaster Posts: 4053
Joined: Tue May 24,
Total Likes:23

### Re: Secondary School Mathematics

Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA

mathtuition88
BlackBelt Posts: 901
Joined: Thu Apr 25,
Total Likes:16

### Re: Secondary School Mathematics

PiggyLalala wrote:Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA
Dear Sir/Mdm,

Best wishes.

PiggyLalala
KiasuGrandMaster Posts: 4053
Joined: Tue May 24,
Total Likes:23

### Re: Secondary School Mathematics

mathtuition88 wrote:
PiggyLalala wrote:Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA
Dear Sir/Mdm,

Best wishes. very much for the solution. Was using the wrong approach- change of base n made a big mess... haha..

I did not think of letting y = the log expression n change it into its exponential form.

Thank you so much.

mathtuition88
BlackBelt Posts: 901
Joined: Thu Apr 25,
Total Likes:16

### Re: Secondary School Mathematics

PiggyLalala wrote:
mathtuition88 wrote:
PiggyLalala wrote:Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA
Dear Sir/Mdm,

Best wishes. very much for the solution. Was using the wrong approach- change of base n made a big mess... haha..

I did not think of letting y = the log expression n change it into its exponential form.

Thank you so much.
You are welcome, glad to help. That question is quite creative, enjoyed solving it.

Qwertymum
YellowBelt Posts: 11
Joined: Wed Dec 21,

### Re: Secondary School Mathematics

My son asks me a Math question from his MY Revision Paper which I need help. Find it rather challenging! Or if there is something not right? Could anyone out there kindly help to solve, thanks in advance.

" A father in his will left all his money to his children as such: \$1000 and 1/10 of what then remains to the first born; then \$2000 and 1/10 of what then remains to the second; then \$3000 and 1/10 of what then remains to the third born; and so no. When this was done each child had the same amount. How many children were there? "

jieheng
BrownBelt Posts: 613
Joined: Thu Mar 24,
Total Likes:3

### Re: Secondary School Mathematics

Qwertymum wrote:My son asks me a Math question from his MY Revision Paper which I need help. Find it rather challenging! Or if there is something not right? Could anyone out there kindly help to solve, thanks in advance.

" A father in his will left all his money to his children as such: \$1000 and 1/10 of what then remains to the first born; then \$2000 and 1/10 of what then remains to the second; then \$3000 and 1/10 of what then remains to the third born; and so no. When this was done each child had the same amount. How many children were there? "
Father's money [-1000-][1U][-------------------9U-------------------]
Father's money [-1000-][1U][--2000--][1P][-----------9P-----------]

Father's money = 1000 + 10U

the money that 1st child will receive = 1000 + 1U

the money that 2nd child will receive = 2000 + 1P

Each child will receive the same amount of money
1000 + 1U = 2000 + 1P
1U = 1000 + 1P ------------(1)

9U = 2000 + 10P ----------(2)

(1)*9 , 9U = 9000 + 9P ---(3)

(2) = (3) ,

2000 + 10P = 9000 + 9P
1P = 7000

From (1)
1U = 1000 + 1P = 1000 + 7000 = 8000

Father's money = 1000 + 10U = 1000 + 10*8 = 81000

the amount of money that each child will receive = 1000 + 1U = 9000

No of children = 81000 / 9000 = 9

Qwertymum
YellowBelt Posts: 11
Joined: Wed Dec 21,

### Re: Secondary School Mathematics

jieheng wrote:
Qwertymum wrote:My son asks me a Math question from his MY Revision Paper which I need help. Find it rather challenging! Or if there is something not right? Could anyone out there kindly help to solve, thanks in advance.

" A father in his will left all his money to his children as such: \$1000 and 1/10 of what then remains to the first born; then \$2000 and 1/10 of what then remains to the second; then \$3000 and 1/10 of what then remains to the third born; and so no. When this was done each child had the same amount. How many children were there? "
Father's money [-1000-][1U][-------------------9U-------------------]
Father's money [-1000-][1U][--2000--][1P][-----------9P-----------]

Father's money = 1000 + 10U

the money that 1st child will receive = 1000 + 1U

the money that 2nd child will receive = 2000 + 1P

Each child will receive the same amount of money
1000 + 1U = 2000 + 1P
1U = 1000 + 1P ------------(1)

9U = 2000 + 10P ----------(2)

(1)*9 , 9U = 9000 + 9P ---(3)

(2) = (3) ,

2000 + 10P = 9000 + 9P
1P = 7000

From (1)
1U = 1000 + 1P = 1000 + 7000 = 8000

Father's money = 1000 + 10U = 1000 + 10*8 = 81000

the amount of money that each child will receive = 1000 + 1U = 9000

No of children = 81000 / 9000 = 9 Wow! That's fast. Thanks a lot.

alwaysLovely
YellowBelt Posts: 19
Joined: Wed Jan 14,

### Re: Cubic Equations

Solving cubic equations is taught in Secondary 3 Additional Maths.

There are three methods:
1) Synthetic division
2) Comparing coefficients
3) Long division

I've two videos on demonstrating how to solve a cubic equation using the first two methods.

I believe this post will be useful for you.
http://www.singaporeolevelmaths.com/201 ... nts-video/

Cheers!