Hi all Maths guru,
there is a sec3 maths qns (elearning) that I don't understd the steps and working given . The questions is below, I seek somebody who can provide me with easy explaination
Question
Mrs Tan takes 1 day more to finish marking the mathematics exam papers of all the 36 students in her class as compared to Mr Wong. If Mrs Tan marked the papers together with Mr Wong, both of them would complete the marking in 2 days. Find the time, in minutes, Mr Wong would take to mark a paper alone. Correct your answer to 3 sigificant figures
[A] 142 mins [B] 22.5 mins [C] 121 mins [D] 41.0 min
Secondary 3 Elearning Maths question
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bluesky63  YellowBelt
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Re: Secondary 3 Elearning Maths question
by n00bin4t0r » Mon Jan 21, 2013 1:24 pm
All these are in rates (no of papers marked) per hour.
Let x be the number of days Wong takes to mark 36 papers.
Wong's rate = 36/x
Tan's rate = 36/(x+1)
Combined rate = (72x+36)/(x(x+1))
Combined duration = 2
Combined duration = 36/Combine rate
36/Combined rate = 2
... solve for x, remember to reject nonlogical answers if there are 2 solution
Answer = x/36 (in papers per days) = ??? (in papers per minute)
I'm sure there are many ways to do this, but here's my thought process.
I have to find Wong's rate, so I let it be x.
Then, I have to get an equation where x is the only unknown so I can solve it.
A quick scan through & by gut feeling, its the equation that equates to 2.
So, I need the lefthandside of that equation, the combined duration which requires the combined rate which in turn requires the individual rates of Tan & Wong.
So, I express Tan & Wong's rate in x, substitute to get their combined rate, then substitute to get combined duration and solve for x
Let x be the number of days Wong takes to mark 36 papers.
Wong's rate = 36/x
Tan's rate = 36/(x+1)
Combined rate = (72x+36)/(x(x+1))
Combined duration = 2
Combined duration = 36/Combine rate
36/Combined rate = 2
... solve for x, remember to reject nonlogical answers if there are 2 solution
Answer = x/36 (in papers per days) = ??? (in papers per minute)
I'm sure there are many ways to do this, but here's my thought process.
I have to find Wong's rate, so I let it be x.
Then, I have to get an equation where x is the only unknown so I can solve it.
A quick scan through & by gut feeling, its the equation that equates to 2.
So, I need the lefthandside of that equation, the combined duration which requires the combined rate which in turn requires the individual rates of Tan & Wong.
So, I express Tan & Wong's rate in x, substitute to get their combined rate, then substitute to get combined duration and solve for x

n00bin4t0r  YellowBelt
 Posts: 18
 Joined: Thu Jan 10, 2013 5:30 pm
 Total Likes: 0
Re: Secondary 3 Elearning Maths question
by bluesky63 » Mon Jan 21, 2013 2:22 pm
Hi
Thanks, l will try it out
Thanks, l will try it out
n00bin4t0r wrote:All these are in rates (no of papers marked) per hour.
Let x be the number of days Wong takes to mark 36 papers.
Wong's rate = 36/x
Tan's rate = 36/(x+1)
Combined rate = (72x+36)/(x(x+1))
Combined duration = 2
Combined duration = 36/Combine rate
36/Combined rate = 2
... solve for x, remember to reject nonlogical answers if there are 2 solution
Answer = x/36 (in papers per days) = ??? (in papers per minute)
I'm sure there are many ways to do this, but here's my thought process.
I have to find Wong's rate, so I let it be x.
Then, I have to get an equation where x is the only unknown so I can solve it.
A quick scan through & by gut feeling, its the equation that equates to 2.
So, I need the lefthandside of that equation, the combined duration which requires the combined rate which in turn requires the individual rates of Tan & Wong.
So, I express Tan & Wong's rate in x, substitute to get their combined rate, then substitute to get combined duration and solve for x

bluesky63  YellowBelt
 Posts: 18
 Joined: Tue Jul 12, 2011 9:18 am
 Total Likes: 0
Re: Secondary 3 Elearning Maths question
by FrekiWang » Mon Jan 21, 2013 3:54 pm
one day may not/should not be 24hour x 60min, not realistic

FrekiWang  GreenBelt
 Posts: 138
 Joined: Tue Mar 08, 2011 11:45 pm
 Total Likes: 0
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