It's a linguistics game.BigDevil wrote:I am under the impression that excess shortage formula isChan09 wrote:Plse help as I don't get the same answer using the excess shortage formulas vs doing this using multiple:

Mr lim has some pencils. If he ties them in bundles of 6 he will have 5 extra pencils. If he ties them in bundles of 5 he will be short of 3. What is the smallest possible number of pencils he has?

If I use excess shortage formulae : 5+3=8, difference 6 -5=1, then 8/1=8, 8*5=40, 40-3=37 but using multiple method the answer is 17. Plse advise, tks

applicable only when there is a fixed number of sets?

Eg. Ms Chan gave 5 sweets to each of her students and had 5 extra.

When she gave them 6 sweets each, she was short of 3.

In the example above, the number of sets (students) does not change from

the first scenario to the second.

But in the question which you asked, the number of sets changed from

2 bundles of 6 pencils + 5 extra to

3 bundles of 5 pencils + 2 extra

Hence applying excess shortage formula in this situation is not correct.

Just my opinion...dunno if there's a variation of the formula

which can be used for such question.

2 bundles of 6 pencils + 5 extra is the same as 3 bundles of 6 pencils with 1 short.

Just as 4 bundles of 5 pencils with 3 short is the same thing as 3 bundles of 5 pencils + 2 extra.

And we end up with the same number of bundles.

Why are the 5 extra pencils not a 'bundle' when the 2 extra pencils are a 'bundle'? Mr Lim is a very confused and inconsistent person.

The shortage excess method can still be used, but must change the point of reference. Then again, the setter probably intends the question to be solved using the list and compare method.