Q&A - P5 Math

Academic support for Primary 5
Suz855
BlueBelt
Posts: 350
Joined: Wed May 13,
Total Likes:2

Re: Q&A - P5 Math

Jerico wrote:Can someone please help to solve the following question :-
(Can it be solved by model drawing ?)

A baker had 400 chocolate muffins and 800 blueberry muffins. 1/5 of all the muffins turned bad. The baker sold 160 chocolate muffins and 300 blueberry muffins. If he had 240 fewer chocolate muffins than blueberry muffins(a) What fraction of all the muffins were sold ?
(Give your answer in the simplest form)
(b) how many chocolate muffins turned bad ?

Tks.
a) 460/1200=23/60

b) 1/5 x 1200= 240

240 + 160 + 300 = 700 ( sold + bad)

Total muffin left 1200 - 700= 500

Left
B [1u][240] } 500
C [1u]

Choc muffin left
(500 -240)/2=130

Choc bad --> 400 - 160 - 130= 110

jwxh
GreenBelt
Posts: 180
Joined: Thu Nov 18,

Re: Q&A - P5 Math

john baked some cookies. 1/3 of the cookies were chocolate cookis and the rest were walnut cookies. After selling 46 chocolate cookies and 32 walnut cookies, there were 6 times as many walnut cookies as chocolate cookies left. How many cookies did john bake at first?

tks

BigDevil
ClassMonitor
Posts: 9246
Joined: Thu Jul 02,
Total Likes:31

Re: Q&A - P5 Math

Suz855 wrote:
BigDevil wrote:1/6 of A's stickers is as many as 2/7 of B's stickers.
If A had 380 stickers in all, how many stickers does B have?

I didn't copy the question wrong. Can it be solved?
Think should be if they had 380 stickers in all, then yes it can be solved by just making the numerator the same (equal fraction concept)
1/6 A = 2/7 B
2/12 A = 2/7B

A--> 12u, B -->7u

19u--> 380
1u--> 20

B --> 7x20=140

You are absolutely correct!
Have checked with the teacher and the question is indeed wrong.

Thanks!

Kialu
YellowBelt
Posts: 13
Joined: Mon Jul 08,

Re: Q&A - P5 Math

Help me to solve this problem
Angel bought 20 tables& chairs for \$372.She sold 4 chairs away.Then she had the same number of tables and chairs left.Each table cost \$9 more than each chair.How much did she pay for the tables?

yeyewynes
KiasuNewbie
Posts: 7
Joined: Tue May 19,

Re: Q&A - P5 Math

please help to solve this problem:

Shannon and Tammy had a total of 709 beads.
After Shannon bought another 74 beads and Tammy gave away 1/5 of her beads, both of them had the same number of beads left.
Find the number of beads Shannon had at first.

Looking forward on your replies...

yeyewynes
KiasuNewbie
Posts: 7
Joined: Tue May 19,

Re: Q&A - P5 Math

please help on this math problem, ... thanks in advance!

yeyewynes
KiasuNewbie
Posts: 7
Joined: Tue May 19,

Re: Q&A - P5 Math

please help on this

yeyewynes
KiasuNewbie
Posts: 7
Joined: Tue May 19,

Re: Q&A - P5 Math

please help to solve this problem:

Tom had \$4 more than Sheila. Tom spent twice as much money as Sheila. In the end, Sheila had twice as much money as Tom. If they had \$42 altogether at first,
A) How much did Tom spend?
B) How much did Sheila spend?

yeyewynes
KiasuNewbie
Posts: 7
Joined: Tue May 19,

Re: Q&A - P5 Math

yeyewynes wrote:please help to solve this problem:

Shannon and Tammy had a total of 709 beads.
After Shannon bought another 74 beads and Tammy gave away 1/5 of her beads, both of them had the same number of beads left.
Find the number of beads Shannon had at first.

Looking forward on your replies...
can solve this using Algebra ... prob is how to explain to P5 student.

S + T = 709

S + 74 = T - T/5
S = T - T/5 -74
S = (4T - 370)/5

Replace S with the above equation (4T-370)/5

(4T - 370)/5 + T = 709
9T - 370 = 709 x 5
9T = 3545 + 370
9T/9 = 3915/9
T = 435
S = 709 - T
S = 709 - 435
S = 274

Oldschool
GreenBelt
Posts: 139
Joined: Fri Mar 22,

Re: Q&A - P5 Math

yeyewynes wrote:
yeyewynes wrote:please help to solve this problem:

Shannon and Tammy had a total of 709 beads.
After Shannon bought another 74 beads and Tammy gave away 1/5 of her beads, both of them had the same number of beads left.
Find the number of beads Shannon had at first.

Looking forward on your replies...
can solve this using Algebra ... prob is how to explain to P5 student.
Hi,

You can try using MD.

Regards