Q&A - P5 Math

Academic support for Primary 5
Locked
speedmaths.com
BrownBelt
BrownBelt
Posts: 559
Joined: Mon Oct 12,
Total Likes:3

Re: Q&A - P5 Math

Post by speedmaths.com » Thu Aug 21, 2014 11:41 pm

belnanna wrote:
Sruthi wrote:Kindly help mw with this question .Image

Thank you in advance

hi can anyone please me on thid question .

thanks a lot in advance
Please can someone solve this.. thanks in advance!!!

Hi Sruthi.

Let’s try another (slightly different) solution:

APD → BPC → 24 cm sq
(Because DP = PC)

APD + BPC → 48 cm sq

ABP + DPC → APD + BPC → 48 cm sq
(A Mathematical Law)

ABP + DPC → 48 cm sq

ABP → 48 – 16 = 32 cm sq


APD → BPC → 24 cm sq

APD → 24 cm sq

APQ : QPD → 1 : 3 → 6 : 18
(AQ is 1/3 of QD)

APQ → 6 cm sq

ABPQ → ABP + APQ → 32 + 6 = 38 cm sq



Hope this helps

Cheers


speedmaths
.

Daddy
BlueBelt
BlueBelt
Posts: 247
Joined: Thu Apr 30,

Re: Q&A - P5 Math

Post by Daddy » Fri Aug 22, 2014 7:37 am

Thanks speedmaths

Sruthi
BlueBelt
BlueBelt
Posts: 243
Joined: Thu Nov 12,

Re: Q&A - P5 Math

Post by Sruthi » Fri Aug 22, 2014 5:39 pm

Thanks a lot speedmaths for your detailed explanation ..

tracywham
OrangeBelt
OrangeBelt
Posts: 84
Joined: Thu Jun 23,

Re: Q&A - P5 Math

Post by tracywham » Sat Aug 23, 2014 4:17 pm

Hi, need help to solve this question:

Mrs Yeo had 60% more books than Mrs Lim. Miss Tang had 25% fewer books than Mrs Yeo. Mrs Yeo and Mrs Lim gave Miss Tang a number of books in the ration 3 : 1. As a result, Miss Tange had 1.5 times as many books as before. Given that Mrs Yeo had 240 books more than Mrs Lim in the end, how many books did Mrs Yeo give to Miss Tang?

Sruthi
BlueBelt
BlueBelt
Posts: 243
Joined: Thu Nov 12,

Re: Q&A - P5 Math

Post by Sruthi » Sat Aug 23, 2014 5:10 pm

Image --> Can anyone please explain the question ..?

Many Thanks in Advance


Sruthi
BlueBelt
BlueBelt
Posts: 243
Joined: Thu Nov 12,

Re: Q&A - P5 Math

Post by Sruthi » Sat Aug 23, 2014 5:13 pm

Image . I need help to solve this problem .

Please help .

Thanks a lot ..

Oldschool
GreenBelt
GreenBelt
Posts: 139
Joined: Fri Mar 22,

Re: Q&A - P5 Math

Post by Oldschool » Sun Aug 24, 2014 2:56 pm

Sruthi wrote:Image . I need help to solve this problem .

Please help .

Thanks a lot ..

Hi,

I will just continue from where you have stopped.

Image

Regards

Sruthi
BlueBelt
BlueBelt
Posts: 243
Joined: Thu Nov 12,

Re: Q&A - P5 Math

Post by Sruthi » Sun Aug 24, 2014 3:14 pm

Thanks a lot for your help

pokemon
BlueBelt
BlueBelt
Posts: 311
Joined: Tue Jul 21,
Total Likes:1

Re: Q&A - P5 Math

Post by pokemon » Sun Aug 24, 2014 4:52 pm

Can someone help me with this ratio problem. Thanks!

Hanson had some one-dollar coins and some fifty-cent coins. The ratio of the number of one-dollar coins to the number of fifty-cent coins he had was 2 : 5. Hanson took 140 fifty-cent coins to the bank and changed these fifty-cent coins for the same value of one-dollar coins. In the end, the number of one-dollar coins to the number of fifty-cent coins he had became 5 : 2. Find the value of the fifty-cent coins Hanson had at first.

alfretztay
KiasuGrandMaster
KiasuGrandMaster
Posts: 1199
Joined: Sun Sep 12,
Total Likes:5

Re: Q&A - P5 Math

Post by alfretztay » Sun Aug 24, 2014 6:03 pm

tracywham wrote:Hi, need help to solve this question:

Mrs Yeo had 60% more books than Mrs Lim. Miss Tang had 25% fewer books than Mrs Yeo. Mrs Yeo and Mrs Lim gave Miss Tang a number of books in the ration 3 : 1. As a result, Miss Tange had 1.5 times as many books as before. Given that Mrs Yeo had 240 books more than Mrs Lim in the end, how many books did Mrs Yeo give to Miss Tang?
Mrs Yeo : Mrs Lim : Ms Tang
16u : 10u : 12u
-3p -1p +4p
---------- ----------- ------------
16u-3p : 10u-1p : 18u

16u - 3p - (10u - 1p) -> 240
6u - 2p -> 240
3u -1p -> 120

12u + 4p = 18u
6u = 4p
3u = 2p

2p - 1p -> 120
1p -> 120
3p -> 360

Ans : 360 books.

Locked