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Q&A - P5 Math

Academic support for Primary 5
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speedmaths.com
BrownBelt
BrownBelt
Posts: 559
Joined: Mon Oct 12,
Total Likes:3

Re: Q&A - P5 Math

Post by speedmaths.com » Sat Jul 26, 2014 6:12 pm

quekcc wrote:
jojoberry wrote:
Daddy wrote:Hi all,
I have 2 questions to ask.
Image

THANK ALL..
I think the answer should be 210 boys.

You can explain using model or algebra.

Let me do it in model.

Let the number of girls be 10 x ,
then the number of boys will be 10 x + [90]

After 80% boys and 30% girls left, we have remaining

girls: 7 x
boys: 2 x + 18 Note: 90/10 x 2 = 18

Now girls is double of boys, i.e.
7 x = 2 x + 18 + 2 x + 18
so
3 x = 36
= 12

Number of boys at first = 10 x 12 + 90 = 210 (Ans)


Hi,

Yes, answer sh be 210.
(Not 420)

Cheers



speedmaths
.
Top

Daddy
BlueBelt
BlueBelt
Posts: 247
Joined: Thu Apr 30,

Re: Q&A - P5 Math

Post by Daddy » Sun Jul 27, 2014 2:27 pm

Thanks all for the answers.

Q18 answer is 210.

Thank again..
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Daddy
BlueBelt
BlueBelt
Posts: 247
Joined: Thu Apr 30,

Re: Q&A - P5 Math

Post by Daddy » Sun Jul 27, 2014 2:35 pm

Hi,

"triangle BPC is 1/4 of the rectangle. (because P is the midpoint of the width)
so the rectangle's area is 24 x 4 = 96"

How did you know BPC is 1/4 of the rectangle?
Why "the rectangle's area is 24 x 4 = 96"? But the picture have one 16cm2 below and a big triangle on top.

:?
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Daddy
BlueBelt
BlueBelt
Posts: 247
Joined: Thu Apr 30,

Re: Q&A - P5 Math

Post by Daddy » Sun Jul 27, 2014 2:40 pm

Hi,

Not so understand for
"boys: 2 x + 18 Note: 90/10 x 2 = 18"

Thank.
Top

Kangkangteo
BlueBelt
BlueBelt
Posts: 345
Joined: Sun May 11,
Total Likes:1

Re: Q&A - P5 Math

Post by Kangkangteo » Sun Jul 27, 2014 7:56 pm

Daddy wrote:Hi all,
I have 2 questions to ask.
Image

THANK ALL..
DP = PC, so
Area APD = Area BPC = 24 sq cm

Area ABCD = 2 x (Area APD + Area BPC)
= 2 x (24 + 24)
= 96 sq cm

AQ = 1/3 QD, so QD = 3/4 AD
Area QPD = 3/4 Area APD
= 3/4 x 24
= 18 sq cm

96 - 24 - 16 - 18 = 38 sq cm

Area of quadrilateral ABPQ is 38 sq cm
Top


Kangkangteo
BlueBelt
BlueBelt
Posts: 345
Joined: Sun May 11,
Total Likes:1

Re: Q&A - P5 Math

Post by Kangkangteo » Sun Jul 27, 2014 8:06 pm

Daddy wrote:Hi all,
I have 2 questions to ask.
Image

THANK ALL..
G : 100u
B : 100u + 90

20% x (100u + 90)= 20u + 18

70% x 100u = 70u

70u ---> 2 x (20u + 18)

30u --> 36

100u ---> 36/30 x 100 = 120

120 + 90 = 210 boys

There were 210 boys at the fun fair at first.
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alfretztay
KiasuGrandMaster
KiasuGrandMaster
Posts: 1199
Joined: Sun Sep 12,
Total Likes:5

Re: Q&A - P5 Math

Post by alfretztay » Sun Jul 27, 2014 8:27 pm

Daddy wrote:Hi,

"triangle BPC is 1/4 of the rectangle. (because P is the midpoint of the width)
so the rectangle's area is 24 x 4 = 96"

How did you know BPC is 1/4 of the rectangle?
Why "the rectangle's area is 24 x 4 = 96"? But the picture have one 16cm2 below and a big triangle on top.

:?
I hope the following steps will help :-

1.Draw a horizontal and a vertical line through P; and another line joining A and P.
2. One should be able to see four equal triangles above P and another four below it.
3. Hence, "triangle BPC is 1/4 of the rectangle" ABCD.
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alfretztay
KiasuGrandMaster
KiasuGrandMaster
Posts: 1199
Joined: Sun Sep 12,
Total Likes:5

Re: Q&A - P5 Math

Post by alfretztay » Sun Jul 27, 2014 8:36 pm

Daddy wrote:Hi,

Not so understand for
"boys: 2 x + 18 Note: 90/10 x 2 = 18"

Thank.


As "the number of boys will be 10 x + [90]", after 80% boys left, we would have 20% of (10u + 90) = 2u + 18. Hence, "boys: 2 x + 18 Note: 90/10 x 2 = 18."
Top

Bunny27
OrangeBelt
OrangeBelt
Posts: 92
Joined: Wed Jan 26,

P5 Ratio

Post by Bunny27 » Sun Jul 27, 2014 9:03 pm

Hi,
Can someone help me on this problem sum?
1. At first, Maria had $243 and Huimei had $183. Later, eachof them bought a calculator and a dictionary. The dictionary cost twice as much as the calculator. Then the ratio of Maria's money to Huimei's money became 3:2.
a) How much money did Maria have left?
b) What was the cost of each dictionary?

Thank you...
Top

Bunny27
OrangeBelt
OrangeBelt
Posts: 92
Joined: Wed Jan 26,

Re: Q&A - P5 Math

Post by Bunny27 » Sun Jul 27, 2014 9:05 pm

alfretztay wrote:
Daddy wrote:Hi,

Not so understand for
"boys: 2 x + 18 Note: 90/10 x 2 = 18"

Thank.


As "the number of boys will be 10 x + [90]", after 80% boys left, we would have 20% of (10u + 90) = 2u + 18. Hence, "boys: 2 x + 18 Note: 90/10 x 2 = 18."




Bunny27

 Post subject: P5 Ratio

Posted: 27 Jul 2014 21:03 

OrangeBelt
Joined: 26 Jan 2011 21:18
Posts: 69 

Hi,
Can someone help me on this problem sum?
1. At first, Maria had $243 and Huimei had $183. Later, eachof them bought a calculator and a dictionary. The dictionary cost twice as much as the calculator. Then the ratio of Maria's money to Huimei's money became 3:2.
a) How much money did Maria have left?
b) What was the cost of each dictionary?

Thank you...
Top

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