## Q&A - P5 Math

- geniuskids
- YellowBelt
**Posts:**25**Joined:**Mon Jul 05,

### Re: Q&A - P5 Math

One more question:

Angeline, Joseph, Christina and Evelyn have some collection of Anime figurines. The number of figurines Angeline has is 1/2 the total number of figurines Joseph, Christina and Evelyn have. The number of figurines Joseph has is 1/3 of the total number of figurines Angeline, Christina and Evelyn have. The number of figurines Christina has is 1/4 of the total of what Angeline, Joseph and Evelyn have. If Evelyn has 169 figurines, how many figurines do the four have altogether?

Angeline, Joseph, Christina and Evelyn have some collection of Anime figurines. The number of figurines Angeline has is 1/2 the total number of figurines Joseph, Christina and Evelyn have. The number of figurines Joseph has is 1/3 of the total number of figurines Angeline, Christina and Evelyn have. The number of figurines Christina has is 1/4 of the total of what Angeline, Joseph and Evelyn have. If Evelyn has 169 figurines, how many figurines do the four have altogether?

### Re: Q&A - P5 Math

Try solving based on constant difference, as each bought a shirt at the same price.geniuskids wrote:Hi, can someone please help with this question:

Muthu had $85 and Ali had $235. After buying a shirt each at the same price, Ali found that he had 4 times as much money as Muthu. Find the cost of the shirt.

- geniuskids
- YellowBelt
**Posts:**25**Joined:**Mon Jul 05,

### Re: Q&A - P5 Math

The difference between the 2 is $150. This amount remains unchanged since they each bought the same shirt.geniuskids wrote:I tried to do it like this but couldn't continue.

At the end, Ali has 4 times as much as Muthu.

3 units -> 150

1 unit -> 50

Therefore, in the end, Muthu had $50 left.

Cost of shirt will be $35.

### Re: Q&A - P5 Math

Hi,

Can someone kindly help to solve the following question :-

Q : Sacks A, B and C each contained some sand. John transferred 1/3 of the sand from A to B, then poured 1/3 of the sand from B to C and finally poured 1/3 of the sand from C to A. Now, there are 16 kg of sand in each sack. How much sand was there in each packet initially ?

Thank you in advance for your help !

Can someone kindly help to solve the following question :-

Q : Sacks A, B and C each contained some sand. John transferred 1/3 of the sand from A to B, then poured 1/3 of the sand from B to C and finally poured 1/3 of the sand from C to A. Now, there are 16 kg of sand in each sack. How much sand was there in each packet initially ?

Thank you in advance for your help !

### Re: Q&A - P5 Math

I hope my working is correct.Jerico wrote:Hi,

Can someone kindly help to solve the following question :-

Q : Sacks A, B and C each contained some sand. John transferred 1/3 of the sand from A to B, then poured 1/3 of the sand from B to C and finally poured 1/3 of the sand from C to A. Now, there are 16 kg of sand in each sack. How much sand was there in each packet initially ?

Thank you in advance for your help !

In the end, A = B = C = 16kg

Use working backward method

**1) 1/3 of sand from C to A**

2/3 C = 16, so C had 24 kg and A had 8 at first.

Now A = 8, B = 16, C = 24

**2) 1/3 of sand from B to C**

2/3 B = 16, so B had 24 and C had 16 at first.

Now A = 8, B = 24, C = 16

**3) 1/3 of sand from A to B**

2/3 A = 8, so A had 12 and B had 20 at first.

Therefore, A = 12, B = 20, C = 16 at first.

**Counter check**

A = 12, B = 20, C = 16 initially

1) 1/3 from A to B

A = 8, B = 24

2) 1/3 from B to C

B = 16, C = 24

3) 1/3 from C to A

C = 16, A = 16

Cheers!

### Re: Q&A - P5 Math

geniuskids wrote:Hi anyone, is something missing in the question to find the answer?

Catherine spent some money on 16 blouses. She spent the same amount of money on another 12 skirts. Each skirt cost $5 more than a blouse. How much money did she spend altogether?

[_____16u_____] cost of blouses

[___12(u+5)___] cost of skirts

Can you solve now?

- MathIzzzFun
- KiasuGrandMaster
**Posts:**2358**Joined:**Wed Mar 09,**Total Likes:**5

### Re: Q&A - P5 Math

Another approach:BigDevil wrote:geniuskids wrote:Hi anyone, is something missing in the question to find the answer?

Catherine spent some money on 16 blouses. She spent the same amount of money on another 12 skirts. Each skirt cost $5 more than a blouse. How much money did she spend altogether?

[_____16u_____] cost of blouses

[___12(u+5)___] cost of skirts

Can you solve now?

16 blouses --> 12 skirts

1 blouse --> 12/16 skirts = 3/4 skirt

1 blouse --> 3u

1 skirt --> 4u

1skirt cost $5 more than 1 blouse

1u --> $5

TOtal amount spent --> 4 x $5 x 12 x 2 = $480

cheers.

### Re: Q&A - P5 Math

Hi,

Can someone please help to solve the following critical thinking problem ? Is there a formula to use to solve this problem with using the tedious manual method of adding up all the odd numbers /

Thank you in advance for your kind assistance.

- speedmaths.com
- BrownBelt
**Posts:**559**Joined:**Mon Oct 12,**Total Likes:**3

### Re: Q&A - P5 Math

Hi,Jerico wrote:

Hi,

Can someone please help to solve the following critical thinking problem ? Is there a formula to use to solve this problem with using the tedious manual method of adding up all the odd numbers /

Thank you in advance for your kind assistance.

Try:

1 × 1 × 1 = 1

2 × 2 × 2 = 8

And so on.

Cheers.

speedmaths

.