## Q&A - PSLE Math

### Re: Q&A - PSLE Math

Can anyone help? Thank you!

A coin box contained only twenty-cent and fifty-cent coins in the ratio of 4:5. When 16 fifty-cent coins were taken out and replaced by some twenty-cent coins, the number of fifty-cent coins left in the box was 7/8 of the twenty-cent coins. The total value of all the coins remained the same. Find the sum of money in the coin box. (Ans $112.20)

A coin box contained only twenty-cent and fifty-cent coins in the ratio of 4:5. When 16 fifty-cent coins were taken out and replaced by some twenty-cent coins, the number of fifty-cent coins left in the box was 7/8 of the twenty-cent coins. The total value of all the coins remained the same. Find the sum of money in the coin box. (Ans $112.20)

- PiggyLalala
- KiasuGrandMaster
**Posts:**4053**Joined:**Tue May 24,**Total Likes:**23

### Re: Q&A - PSLE Math

I think u shld not make the denominator the same because the given condition is number of men = number of women. Not number of male audience = number of female audience. Male audience here refers to the number of male adults (man) and male children. Likewise for the female adults.angel wrote:1190 people watched a movie. 2/5 of the male audience and 1/7 of the female audience were children. There were an equal number of men and women. How many audience were women?

(I always get stuck with questions like these. I worked on same denominator, then I'm stuck as I am confused its total 35 units or 70. )

The correct solution is posted by nebbermind and ender.

### Re: Q&A - PSLE Math

Bunnyng wrote:Can anyone help? Thank you!

A coin box contained only twenty-cent and fifty-cent coins in the ratio of 4:5. When 16 fifty-cent coins were taken out and replaced by some twenty-cent coins, the number of fifty-cent coins left in the box was 7/8 of the twenty-cent coins. The total value of all the coins remained the same. Find the sum of money in the coin box. (Ans $112.20)

OR

### Re: Q&A - PSLE Math

Another explanation:Bunnyng wrote:Can anyone help? Thank you!

A coin box contained only twenty-cent and fifty-cent coins in the ratio of 4:5. When 16 fifty-cent coins were taken out and replaced by some twenty-cent coins, the number of fifty-cent coins left in the box was 7/8 of the twenty-cent coins. The total value of all the coins remained the same. Find the sum of money in the coin box. (Ans $112.20)

### Re: Q&A - PSLE Math

Ps help the following qns. Many tks and God Bless:)

(1) Alice, Betty and Charlotte had a total of 640 marbles at first. The ratio of Betty's marbles to Charlotte's marbles was 5:4. After Alice and Betty each had lost 50% of their marbles, the three girls had 440 marbles. How many marbles did Alice have at first?

(2) Miss Tang bought 164 strawberry and orange sweets altogether. They were repacked into two boxes, A and B. The ratio of the number of strawberry sweets in Box A to that in Box B was 3:2. The number of orange sweets in Box A was 1/3 as many as that in Box B. If there were 40 more sweets in Box B than A, how many strawberry sweets were there in Box A?

(1) Alice, Betty and Charlotte had a total of 640 marbles at first. The ratio of Betty's marbles to Charlotte's marbles was 5:4. After Alice and Betty each had lost 50% of their marbles, the three girls had 440 marbles. How many marbles did Alice have at first?

(2) Miss Tang bought 164 strawberry and orange sweets altogether. They were repacked into two boxes, A and B. The ratio of the number of strawberry sweets in Box A to that in Box B was 3:2. The number of orange sweets in Box A was 1/3 as many as that in Box B. If there were 40 more sweets in Box B than A, how many strawberry sweets were there in Box A?

### Re: Q&A - PSLE Math

SOS mum wrote:Ps help the following qns. Many tks and God Bless:)

(1) Alice, Betty and Charlotte had a total of 640 marbles at first. The ratio of Betty's marbles to Charlotte's marbles was 5:4. After Alice and Betty each had lost 50% of their marbles, the three girls had 440 marbles. How many marbles did Alice have at first?

### Re: Q&A - PSLE Math

SOS mum wrote:Ps help the following qns. Many tks and God Bless:)

(2) Miss Tang bought 164 strawberry and orange sweets altogether. They were repacked into two boxes, A and B. The ratio of the number of strawberry sweets in Box A to that in Box B was 3:2. The number of orange sweets in Box A was 1/3 as many as that in Box B. If there were 40 more sweets in Box B than A, how many strawberry sweets were there in Box A?

### Re: Q&A - PSLE Math

Hi, ps help. Many tks and God Bless:)

In a swimming club, the ratio of the number of girls to the number of boys was 5:3. After 3 girls and 5 boys joined the club, the ratio became 7:5. How many girls were there in the club at first?

In a swimming club, the ratio of the number of girls to the number of boys was 5:3. After 3 girls and 5 boys joined the club, the ratio became 7:5. How many girls were there in the club at first?

### Re: Q&A - PSLE Math

G : BSOS mum wrote:Hi, ps help. Many tks and God Bless:)

In a swimming club, the ratio of the number of girls to the number of boys was 5:3. After 3 girls and 5 boys joined the club, the ratio became 7:5. How many girls were there in the club at first?

5u : 3u

After adding more children,

G : B

5u+3 : 3u+ 5

7 : 5

So (5u+3) / (3u+5) = 7/5

5(5u+3) = 7(3u+5)

25u + 15 = 21u+35

4u = 20

u = 5

**Girls at first = 5u = 5 x 5 = 25**