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Q&A - PSLE Math

Academic support for Primary 6 and PSLE
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Yerdua
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Re: Q&A - PSLE Math

Post by Yerdua » Fri Aug 07, 2015 11:47 am

Image
Pls help with this 5marks qn. Thanks!
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sushi88
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Re: Q&A - PSLE Math

Post by sushi88 » Fri Aug 07, 2015 12:20 pm

Yerdua...please repost question...cannot read the whole question.
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Ender
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Re: Q&A - PSLE Math

Post by Ender » Fri Aug 07, 2015 1:35 pm

Yerdua wrote:Image
Pls help with this 5marks qn. Thanks!
Find the areas of the square, quadrant and semicircle first.

Square - quadrant + semicircle = 2x +(w+y) ...... Note (w+y) = 2x
Square - quadrant + semicircle = 4x
Area of x = 4x/4

The method used is to mapped the region w, x , y and z with the above areas
When you add the area of square, region w, x, y, and z is marked with 1.
Minus the area of quadrant. y and z becomes 0. While w and x remain as 1.
Add the semicircle, y becomes 1 and x becomes 2.
Final result is z is 0, w and y are 1 count each and x is 2 counts. I.e 2x + (w+y).
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ozora
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Re: Q&A - PSLE Math

Post by ozora » Fri Aug 07, 2015 11:34 pm

Need some help in geometry Image thanks
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Nebbermind
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Re: Q&A - PSLE Math

Post by Nebbermind » Sat Aug 08, 2015 12:54 am

ozora wrote:Need some help in geometry Image thanks
SBA = ABE = (180 - 108)/2 = 36

BAE = 180 - (36 + 79)

CSA = AEB = 79

TSC = 90 - 79 = 11

SCT = BCD = 90 - 11 = 79
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ozora
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Re: Q&A - PSLE Math

Post by ozora » Sat Aug 08, 2015 10:20 am

Nebbermind wrote:
ozora wrote:Need some help in geometry Image thanks
SBA = ABE = (180 - 108)/2 = 36

BAE = 180 - (36 + 79)

CSA = AEB = 79

TSC = 90 - 79 = 11

SCT = BCD = 90 - 11 = 79
Thank u
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Jerico
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Re: Q&A - PSLE Math

Post by Jerico » Sat Aug 08, 2015 8:43 pm

Hi, Can Someone please help ? Thank you in advance !

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Jerico
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Re: Q&A - PSLE Math

Post by Jerico » Sat Aug 08, 2015 8:45 pm

Hi, Can someone please help ? Thank you in advance !

Image
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Jerico
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Re: Q&A - PSLE Math

Post by Jerico » Sat Aug 08, 2015 8:47 pm

Hi, Can someone please help ? Thank you in advance !

Image
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Jerico
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Re: Q&A - PSLE Math

Post by Jerico » Sat Aug 08, 2015 8:49 pm

Hi, Can someone please help ? Thank you in advance !

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