6u + 60 =3p

5u-40=2p

4u+40 =2p

5u-40=4U+40

1U = 80

80X 6 = 480 [goose]

4x80+40 =360 [Duck ]

480-360 =

**120**

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Post
by **NerdyMath** » Fri Sep 25, 2015 12:54 am

hoddle wrote:Hi

Need help on the below.

28x18x15x4/5=6048

Find the base area.

Base area of A: base area of B

28x18 : 168

504 : 168

1.5 times x 168 = 252

6048/(252+504)= 8

8 x 252 = 2016 cm3

Solved by DS.

Last edited by NerdyMath on Fri Sep 25, 2015 11:47 am, edited 1 time in total.

Post
by **NerdyMath** » Fri Sep 25, 2015 1:12 am

hoddle wrote:Hi

Need help on the below.

24 x 6/10 = 14.4 papaya (sold)

24 x 4/10 = 9.6 papaya (left)

6/10 and 3/4 , the common denominator is 20

6/10= 12/20(papaya sold)

3/4= 15/20(apple sold)

Hence, 8/20 (papaya) and 5/20 (apple) will be left.

Also, don't forget about the 9.6 papaya earlier.

[][][][][][][][][9.6]

[][][][][]<---30-->

3u -> 30-9.6= 20.4

1u -> 20.4/3= 6.8

6.8 x 12 + 14.4 x $2.30 = $220.80

$0.40 x 15 x $6.80 = 40.80

$220.80+$40.80 = $261.60

(Sorry for the mistake! Was doing it late at night)

Last edited by NerdyMath on Fri Sep 25, 2015 11:50 am, edited 1 time in total.

Post
by **NerdyMath** » Fri Sep 25, 2015 1:15 am

Find that this is a great place for DS to help others, build a stronger foundations and be exposed to more questions. Hence, DS will be here to solve questions! Also, do pardon DS if his explanation/method is not clear.

Post
by **Ender** » Fri Sep 25, 2015 10:26 am

for the same duration,Sruthi wrote: -please help me with this question.

Distance travelled by Eunike = 4/5 => 12/15

Distance traveled by Arthur = 2/3 => 10/15

Therefore ratio of distance traveled for the same duration E : A => 12:10=>6:5

Speed ratio is the same as above E : A = > 6u:5U

6u-5u = 12

u=12

Arther's speed is 5u = 5(12) =60km/h

Post
by **Ender** » Fri Sep 25, 2015 10:31 am

this question was posted before,Sruthi wrote: -please help me with this question

Scenario 1 :

Flow rate into Tank A : B => 3:5 , Capacity of B = B- 5 litre

Scenario 2

Flow rate into Tank A:B =>4:3 , Capacity of B = 2XB

Common the A, as both scenario they filled completely, and hence both represent the capacity of A.

1) A:B=> 3:5 => 12u:20u , Capacity of B = 20u-5

2) A:B=> 4:3=> 12u:9u , Capacity of B = 2X9u= 18u

20u-5 = 18u

2u=5

u=2.5

Capacity of B = 18u=18(2.5) = 45 litre.

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**Posts:**1199**Joined:**Sun Sep 12,**Total Likes:**5

Post
by **alfretztay** » Fri Sep 25, 2015 10:46 am

7A + 7B ——- (4A + 4B) + 7A + 1Bacehkr3009 wrote:Hi Please advise on this question:

Machine A and Machine B working together take 7 days to finish producing 100 boxes of toys.

Mr Lee switched on Machine A and Machine B for 4 days, followed by Machine A alone for 7 days. Then he needed to switch on Machine B alone for 1 more day to complete producing the same 100 boxes of toys.

How long will Machine A alone take to produce the 100 boxes of toys?

Thanks in advance.

2B ——- 4A

1B ——- 2A

7A + 7B ——- 7A + 7 x 2A = 21A

Ans : 21 days.

Post
by **Ender** » Fri Sep 25, 2015 10:53 am

PlayfulFairy wrote:In a factory , 585 of the workers are Chinese, 3/11 of the remainder are Malays and the rest are Indians. The Indians form 1/3 of the total number of workers. 1/2 of the Indians and 5/9 of the Malays are males.

(A) how many workers are there in the factory altogether?

(B) what is the ratio of the number of Indian male workers to the number of Malay male workers? Give your answer in its simplest form.

Please help. Thanks!!

Code: Select all

```
Chinese(585)
/
Total Workers Malay (3/11)
\ /
Others(?)
\
Indian (8/11)
```

Others = 1/3 X 11/8 = 11/24

a) Therefore chinese make up of 24/24 -11/24 = 13/24

13/24 => 585

24/24 => 1080

b)Out of others,

Malays => 3/11 =>9/33

Males is 5/9 => 5/33

Indians=>8/11=>24/33

Males is 1/2=>12/33

Indian Male : Malay Male => 12:5

Post
by **Ender** » Fri Sep 25, 2015 10:56 am

http://www.kiasuparents.com/kiasu/forum ... 3#p1530583

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