questionable_i wrote:Can anyone help me with these questions?

1. Mrs Lim will make a profit which is 19% of the import price if she sells the necklace at $4165. What will be her profit if she sells the necklace at $4270 and the import price of the necklace remains constant?

2. Students are donating money to a charity fund that helps less privileged kids. The number of $2, $5 and $10-notes donated are in the ratio of 9 : 2 : 5.

4/9 of the $2-notes and 10 $5-notes are taken out. The remaining notes are worth $300. How many $10-notes are there?

## Q&A - PSLE Math

### Re: Q&A - PSLE Math

- forestcadee
- GreenBelt
**Posts:**162**Joined:**Thu Jun 24,

### Re: Q&A - PSLE Math

forestcadee wrote:Hi, can someone help to solve the following 2 questions on circles? Thank you.

**(1/2)*(3.14*12*12) = 226.08 cm^2 ==> 226cm^2**

Last edited by Ice watch on Mon Mar 21, 2016 2:40 am, edited 1 time in total.

### Re: Q&A - PSLE Math

forestcadee wrote:Hi, can someone help to solve the following 2 questions on circles? Thank you.

**(1/3)*(3.14*10*10) = 104.67 cm^2 ==> 105cm^2**

- forestcadee
- GreenBelt
**Posts:**162**Joined:**Thu Jun 24,

### Re: Q&A - PSLE Math

1190 people watched a movie. 2/5 of the male audience and 1/7 of the female audience were children. There were an equal number of men and women. How many audience were women?

(I always get stuck with questions like these. I worked on same denominator, then I'm stuck as I am confused its total 35 units or 70. )

(I always get stuck with questions like these. I worked on same denominator, then I'm stuck as I am confused its total 35 units or 70. )

### Re: Q&A - PSLE Math

Let total male be 5M and female be 7F

Since there's equal number of Men and Women, therefore 3M = 6F

Hence we can make them common unit. Men is 3 parts, Womem is 6 parts. LCM would be 6

We let Men be 6u, and women be 6u.

Finding total male

3/5 => 6u

5/5 => 10u

Finding total female

6/7 => 6u

7/7 => 7u

Total audience = 17u = 1190

u= 70

Women = 6u = 6(70) = 420

Since there's equal number of Men and Women, therefore 3M = 6F

Hence we can make them common unit. Men is 3 parts, Womem is 6 parts. LCM would be 6

We let Men be 6u, and women be 6u.

Finding total male

3/5 => 6u

5/5 => 10u

Finding total female

6/7 => 6u

7/7 => 7u

Total audience = 17u = 1190

u= 70

Women = 6u = 6(70) = 420

- Nebbermind
- KiasuGrandMaster
**Posts:**16632**Joined:**Tue Dec 22,**Total Likes:**169

### Re: Q&A - PSLE Math

Male: 2U children, 3U menangel wrote:1190 people watched a movie. 2/5 of the male audience and 1/7 of the female audience were children. There were an equal number of men and women. How many audience were women?

(I always get stuck with questions like these. I worked on same denominator, then I'm stuck as I am confused its total 35 units or 70. )

Female: 1P children. 6P women

Since 3U = 6P -> U = 2P,

Total = 10P + 7P = 1190

Find 6P

- questionable_i
- BrownBelt
**Posts:**535**Joined:**Sat Oct 10,**Total Likes:**1

### Re: Q&A - PSLE Math

Ice watchIce watch wrote:questionable_i wrote:Can anyone help me with these questions?

1. Mrs Lim will make a profit which is 19% of the import price if she sells the necklace at $4165. What will be her profit if she sells the necklace at $4270 and the import price of the necklace remains constant?

2. Students are donating money to a charity fund that helps less privileged kids. The number of $2, $5 and $10-notes donated are in the ratio of 9 : 2 : 5.

4/9 of the $2-notes and 10 $5-notes are taken out. The remaining notes are worth $300. How many $10-notes are there?

### Re: Q&A - PSLE Math

Can anyone help? Thank you!

A coin box contained only twenty-cent and fifty-cent coins in the ratio of 4:5. When 16 fifty-cent coins were taken out and replaced by some twenty-cent coins, the number of fifty-cent coins left in the box was 7/8 of the twenty-cent coins. The total value of all the coins remained the same. Find the sum of money in the coin box. (Ans $112.20)

A coin box contained only twenty-cent and fifty-cent coins in the ratio of 4:5. When 16 fifty-cent coins were taken out and replaced by some twenty-cent coins, the number of fifty-cent coins left in the box was 7/8 of the twenty-cent coins. The total value of all the coins remained the same. Find the sum of money in the coin box. (Ans $112.20)