Hi Parents and Students,
Here's a Challenging question for all of you to solve:
Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.
Different letters stand for different singledigit whole numbers.
Have a fun time solving !
Maths Olympiad Challenge!!!
Discussions on tuition centres/enrichment services that specialise in Mathematics.

Maths Hub  BlueBelt
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Re: Maths Olympiad Challenge!!!
by Jojo_2010 » Fri Oct 22, 2010 1:35 pm
7 X ABCDEF = 6 X DEFABC
A=6
B=5
C=4
D=7
E=2
F=3
7X6X5X4X7X2X3=6X7X2X3X6X5X4=30240.
Am i rite?
A=6
B=5
C=4
D=7
E=2
F=3
7X6X5X4X7X2X3=6X7X2X3X6X5X4=30240.
Am i rite?

Jojo_2010  GreenBelt
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Re: Maths Olympiad Challenge!!!
by Maths Hub » Fri Oct 22, 2010 5:53 pm
Jojo_2010 wrote:7 X ABCDEF = 6 X DEFABC
A=6
B=5
C=4
D=7
E=2
F=3
7X6X5X4X7X2X3=6X7X2X3X6X5X4=30240.
Am i rite?
Not Correct
For your equation above, LHS is not equal to RHS.
Anyway, ABCDEF is a 6 digit number, not a product of 6 single digit number.
Last edited by Maths Hub on Fri Oct 22, 2010 9:40 pm, edited 1 time in total.

Maths Hub  BlueBelt
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Re: Maths Olympiad Challenge!!!
by mujin » Fri Oct 22, 2010 8:53 pm
Maths Hub wrote:Hi Parents and Students,
Here's a Challenging question for all of you to solve:
Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.
Different letters stand for different singledigit whole numbers.
Have a fun time solving !
Let me try:
ABCDEF = 461538

mujin  YellowBelt
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 Total Likes: 0
Re: Maths Olympiad Challenge!!!
by mujin » Fri Oct 22, 2010 9:00 pm
mujin wrote:Maths Hub wrote:Hi Parents and Students,
Here's a Challenging question for all of you to solve:
Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.
Different letters stand for different singledigit whole numbers.
Have a fun time solving !
Let me try:
ABCDEF = 461538
My working :
ABCDEF x 7 = DEFABC x 6
[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6
7000 ABC + 7 DEF = 6000 DEF + 6 ABC
6994 ABC = 5993 DEF
538 ABC = 461 DEF
538 (461) = 461 (538)
whereby (461) = (ABC) and
(538) = DEF
so.. ABCDEF = 461538
Hope I am right

mujin  YellowBelt
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Re: Maths Olympiad Challenge!!!
by iFruit » Fri Oct 22, 2010 10:03 pm
mujin wrote:mujin wrote:Maths Hub wrote:Hi Parents and Students,
Here's a Challenging question for all of you to solve:
Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.
Different letters stand for different singledigit whole numbers.
Have a fun time solving !
Let me try:
ABCDEF = 461538
My working :
ABCDEF x 7 = DEFABC x 6
[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6
7000 ABC + 7 DEF = 6000 DEF + 6 ABC
6994 ABC = 5993 DEF
538 ABC = 461 DEF
538 (461) = 461 (538)
whereby (461) = (ABC) and
(538) = DEF
so.. ABCDEF = 461538
Hope I am right
Nice One

iFruit  BlueBelt
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Re: Maths Olympiad Challenge!!!
by Maths Hub » Fri Oct 22, 2010 11:27 pm
iFruit wrote:mujin wrote:mujin wrote:Maths Hub wrote:Hi Parents and Students,
Here's a Challenging question for all of you to solve:
Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.
Different letters stand for different singledigit whole numbers.
Have a fun time solving !
Let me try:
ABCDEF = 461538
My working :
ABCDEF x 7 = DEFABC x 6
[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6
7000 ABC + 7 DEF = 6000 DEF + 6 ABC
6994 ABC = 5993 DEF
538 ABC = 461 DEF
538 (461) = 461 (538)
whereby (461) = (ABC) and
(538) = DEF
so.. ABCDEF = 461538
Hope I am right
Nice One
Well done! This is indeed correct!

Maths Hub  BlueBelt
 Posts: 368
 Joined: Wed Oct 20, 2010 11:52 pm
 Total Likes: 0
by Guest » Fri Oct 22, 2010 11:44 pm
Not easy to see that both sides divisible by 13 to reduce to 538 and 461 leh.....at least not for old mummy like me...
6994 ABC = 5993 DEF
538 ABC = 461 DEF
6994 ABC = 5993 DEF
538 ABC = 461 DEF
 Guest
by Maths Hub » Fri Oct 22, 2010 11:47 pm
Pls refer to http://www.kiasuparents.com/kiasu/forum ... hp?t=14953 for the next Maths Olympiad Challenge!!!

Maths Hub  BlueBelt
 Posts: 368
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by ChiefKiasu » Sat Oct 23, 2010 12:08 am
Maths Hub wrote:Pls refer to http://www.kiasuparents.com/kiasu/forum ... hp?t=14953 for the next Maths Olympiad Challenge!!!
Umm... seems like it is not much of a challenge for the super bright parents and kids we have here right on KiasuParents.com. Maybe need to turn up the difficult by a couple of dozen notches?

ChiefKiasu  Site Admin
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