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Q&A - P5 Math

Academic support for Primary 5
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guchengyouzi
GreenBelt
GreenBelt
Posts: 151
Joined: Sun Apr 27,

Re: Q&A - P5 Math

Post by guchengyouzi » Sun May 18, 2014 1:33 pm

belnanna wrote:
milo-cupcake wrote:Image

Thanks in advance!
I found this question.. Can anyone help please? Thanks..
Based on the ratios of the salaries and savings :
Image
Z salary is 4/5 of J saving
4u = 4/5 * 15k
u = 3k

Z expenditure is 4u - 4k = 12k -4k = 8k
J expenditure 7u - 15k = 21k - 15k = 6k
J : Z = 6k : 8k = 3 : 4
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guchengyouzi
GreenBelt
GreenBelt
Posts: 151
Joined: Sun Apr 27,

Re: Q&A - P5 Math

Post by guchengyouzi » Sun May 18, 2014 1:49 pm

belnanna wrote:Can someone help please.. thanks
Alan had some apples. When he packed them into bags of 7 apples,he would have 3 apples left. When he packed them into bags of 9 apples,he would be short of 6 apples. what was the least number of apples that Alan had?
If Alan packed into n bags of 7,
total no. of apples is n * 7 + 3 = 7n + 3
If packed into k bags of 9,
total no. of apples is k * 9 - 6 = 9k - 6
Therefore,
7n + 3 = 9k - 6
9k = 7n + 9
k = (7/9) n + 1
To get the smallest whole number for k, n should be 9.
n = 9
k = 8
total no. of apples is 7n + 3 = 66
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Jerico
GreenBelt
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Posts: 178
Joined: Tue Jul 28,

Re: Q&A - P5 Math

Post by Jerico » Sun May 18, 2014 9:43 pm

Hi, Can someone kindly help me to solve the following Heuristics Question :-

Q : There are three different numbers.
- They are all four-digit odd numbers.
- The digits of each number add up to 14.
- None of the numbers can be divided by 5.
- These numbers read the same forwards and backwards.

Can you guess the numbers using these clues ?

Thank you in advance for your kind assistance.
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guchengyouzi
GreenBelt
GreenBelt
Posts: 151
Joined: Sun Apr 27,

Re: Q&A - P5 Math

Post by guchengyouzi » Sun May 18, 2014 10:57 pm

Jerico wrote:Hi, Can someone kindly help me to solve the following Heuristics Question :-

Q : There are three different numbers.
- They are all four-digit odd numbers.
- The digits of each number add up to 14.
- None of the numbers can be divided by 5.
- These numbers read the same forwards and backwards.

Can you guess the numbers using these clues ?

Thank you in advance for your kind assistance.
1st is d
2nd is c
3rd is c
4th is d
so the number looks like 'dccd'
d + c + c + d = 14
2c + 2d = 14
c + d = 7

since cannot be divided by 5, d could be 1, 3, 7 or 9
d = 1, c = 6, 1661
d = 3, c = 4, 3443
d = 7, c = 0, 7007
if d = 9, c would become negative
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speedmaths.com
BrownBelt
BrownBelt
Posts: 559
Joined: Mon Oct 12,
Total Likes:3

Re: Q&A - P5 Math

Post by speedmaths.com » Mon May 19, 2014 1:33 am

belnanna wrote:
milo-cupcake wrote:Image

Thanks in advance!
I found this question.. Can anyone help please? Thanks..
Hi,

Another possible solution:

(Zachary's saving is 4/15 of Jeremy's savings.)

Zachary's saving → 4 u
Jeremy's savings → 15 u

Image

(Zachary's monthly salary is 4/5 of Jeremy's savings)
Zachary's monthly salary is 12/15 of Jeremy's savings

Zachary's monthly salary → 12u
Jeremy's savings → 15 u

Image

(Jeremy's monthly salary is 1 3/4 Zachary's monthly salary)
Jeremy's monthly salary is 1 3/4 or 7/4 or 21/12 Zachary's monthly salary.

Jeremy's monthly salary → 21 u
Zachary's monthly salary → 12 u

Image

Jeremy's monthly salary → 21 u
Jeremy's savings → 15 u
Jeremy's expenditure → 21 u – 15 u → 6 u

Zachary's monthly salary → 12 u
Zachary's saving → 4 u
Zachary’s expenditure → 12 u – 4 u → 8 u

Image

Ratio of Jeremy's expenditure to Zachary’s expenditure
→ 6 u : 8 u
→ 3:4


Hope this helps.

Cheers


speedmaths
.
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belnanna
OrangeBelt
OrangeBelt
Posts: 80
Joined: Fri Nov 01,

Re: Q&A - P5 Math

Post by belnanna » Mon May 19, 2014 8:54 pm

Hi, can some kind soul please help without solving this in algebra?
Thanks ....

Tom's present age is twice more than Sam's age years ago. Today, Sam's age is Tom's age the same number of years ago. How old is Tom now if the sum of their present age is 30?
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homeworkgurusg
YellowBelt
YellowBelt
Posts: 20
Joined: Mon Apr 28,

Re: Q&A - P5 Math

Post by homeworkgurusg » Tue May 20, 2014 8:32 pm

belnanna wrote:Hi, can some kind soul please help without solving this in algebra?
Thanks ....

Tom's present age is twice more than Sam's age years ago. Today, Sam's age is Tom's age the same number of years ago. How old is Tom now if the sum of their present age is 30?
Hi, it can be solved using model.

A common mistake by my student is "twice more than", they often mistake it as "twice as much as". In this question, "Tom's present age is twice more than Sam's age years ago", means Tom's present age is 3u, Sam's age years ago is 1u.

Image

Hope this helps.

Cheers.
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belnanna
OrangeBelt
OrangeBelt
Posts: 80
Joined: Fri Nov 01,

Re: Q&A - P5 Math

Post by belnanna » Tue May 20, 2014 8:37 pm

homeworkgurusg wrote:
belnanna wrote:Hi, can some kind soul please help without solving this in algebra?
Thanks ....

Tom's present age is twice more than Sam's age years ago. Today, Sam's age is Tom's age the same number of years ago. How old is Tom now if the sum of their present age is 30?
Hi, it can be solved using model.

A common mistake by my student is "twice more than", they often mistake it as "twice as much as". In this question, "Tom's present age is twice more than Sam's age years ago", means Tom's present age is 3u, Sam's age years ago is 1u.

Image

Hope this helps.

Cheers.
Thank you very much
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dicoyote
OrangeBelt
OrangeBelt
Posts: 32
Joined: Sun Mar 28,

Re: Q&A - P5 Math

Post by dicoyote » Fri May 23, 2014 10:39 am

Hi, can any kind soul help me in this question? Many thanks in advance!

A container contains a number of chocolate n banana muffifns in the ratio 5:2. After removing 10 chocolate muffins n adding another 4 banana muffins, the ratio became 3:2. How many chocolate muffins were there in the container in the end?
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MathIzzzFun
KiasuGrandMaster
KiasuGrandMaster
Posts: 2358
Joined: Wed Mar 09,
Total Likes:5

Re: Q&A - P5 Math

Post by MathIzzzFun » Fri May 23, 2014 11:39 am

dicoyote wrote:Hi, can any kind soul help me in this question? Many thanks in advance!

A container contains a number of chocolate n banana muffifns in the ratio 5:2. After removing 10 chocolate muffins n adding another 4 banana muffins, the ratio became 3:2. How many chocolate muffins were there in the container in the end?

using model/units:


Image

For chocolate muffins,
5u - 10 = 3u + 6
2u --> 16
u --> 8

In the end,
number of chocolate muffins = 3 x 8 + 6 = 30

using units/parts:

Image

Equalizing parts (--> 6p)

10u - 20 = 6u + 12
4u --> 32
u --> 8

In the end,

number of chocolate muffins = 5 x 8 - 10 = 30

cheers.
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