**David takes 3 minutes to fix a jigsaw puzzle. Ryan takes 5 minutes to fix the same jigsaw puzzle. If both of them fix together, how many minutes will take for them to fix the jigsaw puzzle.**

**Answer in Fraction.**

Academic support for Primary 5

Post
by **belnanna** » Thu Aug 14, 2014 12:26 pm

Hi.. Can someone please help with this question.. Thanks in advance!

**David takes 3 minutes to fix a jigsaw puzzle. Ryan takes 5 minutes to fix the same jigsaw puzzle. If both of them fix together, how many minutes will take for them to fix the jigsaw puzzle. **

**Answer in Fraction.**

- raghupavithra
- OrangeBelt
**Posts:**75**Joined:**Tue Dec 07,

Post
by **raghupavithra** » Thu Aug 14, 2014 7:14 pm

Hi

There were 120 more roses than tulips in a florist shop on the first day.On the second day, the florist increased the number of tulips by 30%and sold20% of the roses,resulting in a total of 726 roses and tulips in the florist shop.How many roses did the florist sell on the second day?

Pls help

There were 120 more roses than tulips in a florist shop on the first day.On the second day, the florist increased the number of tulips by 30%and sold20% of the roses,resulting in a total of 726 roses and tulips in the florist shop.How many roses did the florist sell on the second day?

Pls help

- speedmaths.com
- BrownBelt
**Posts:**559**Joined:**Mon Oct 12,**Total Likes:**3

Post
by **speedmaths.com** » Thu Aug 14, 2014 8:03 pm

raghupavithra wrote:Hi

There were 120 more roses than tulips in a florist shop on the first day.On the second day, the florist increased the number of tulips by 30%and sold20% of the roses,resulting in a total of 726 roses and tulips in the florist shop.How many roses did the florist sell on the second day?

Pls help

Hi raghupavithra,

One possible method:

Day 1:

Tulips → (100 Boxes or 100 units or) 100 u

Roses → 100 u + 120

Day 2:

Tulips → 130 u

Roses → 80 u + 96

130 u + 80 u + 96 → 726

210 u → 726 - 96

1 u →

Hope this helps.

Cheers

.

- raghupavithra
- OrangeBelt
**Posts:**75**Joined:**Tue Dec 07,

- raghupavithra
- OrangeBelt
**Posts:**75**Joined:**Tue Dec 07,

- speedmaths.com
- BrownBelt
**Posts:**559**Joined:**Mon Oct 12,**Total Likes:**3

Post
by **speedmaths.com** » Thu Aug 14, 2014 8:55 pm

Hi,raghupavithra wrote:How to get 96

96 is 80% (left) of 120.

.

Post
by **Jerico** » Thu Aug 14, 2014 11:00 pm

Q1 : There were thrice as many beads in Container A than Container B. Container C contains half as many beads as Container B. There were 1206 beads in all the 3 containers. Marcus transferred some marbles from Container A to Container C. As a result, the ratio of the number of beads in Container C to the total number of beads in Container A and B became 5 : 4. How many beads did Marcus transfer from Container A to Container C ?

Q2 : A rectangular tank 28 cm by 15 cm by 30 cm is 7/10 filled with water. Some water from the tank is poured away. The volume of water left in the tank is 1/3 of its capacity when completely filled. What is the decrease in height of the water level in the tank ?

Appreciate your help. Thank you in advance !

Q2 : A rectangular tank 28 cm by 15 cm by 30 cm is 7/10 filled with water. Some water from the tank is poured away. The volume of water left in the tank is 1/3 of its capacity when completely filled. What is the decrease in height of the water level in the tank ?

Appreciate your help. Thank you in advance !

- raghupavithra
- OrangeBelt
**Posts:**75**Joined:**Tue Dec 07,

- speedmaths.com
- BrownBelt
**Posts:**559**Joined:**Mon Oct 12,**Total Likes:**3

Post
by **speedmaths.com** » Fri Aug 15, 2014 3:03 am

Hi Jerico,Jerico wrote:Q1 : There were thrice as many beads in Container A than Container B. Container C contains half as many beads as Container B. There were 1206 beads in all the 3 containers. Marcus transferred some marbles from Container A to Container C. As a result, the ratio of the number of beads in Container C to the total number of beads in Container A and B became 5 : 4. How many beads did Marcus transfer from Container A to Container C ?

Appreciate your help. Thank you in advance !

At first:

A → 6 u

B → 2 u

C → 1 u

Total → 9 u → 1206 beads

After the transfer:

A → 2 u

B → 2 u

C → 5 u

Total → 9 u → 1206 beads

Can you continue from here?

Hope this helps

Cheers

.

Post
by **Er Jie** » Fri Aug 15, 2014 3:57 pm

Hi, would appreciate if someone can help with this question. Thanks in advance.

Mr. Tan had some $5 and $10 notes. The ratio of the number of $5 notes to the number of $10 notes was 1:4. He exchanged twelve pieces of $10 notes for $5 notes. The ratio of $5 notes to $10 notes then became 1:2.

How much money did Mr. Tan have?

Mr. Tan had some $5 and $10 notes. The ratio of the number of $5 notes to the number of $10 notes was 1:4. He exchanged twelve pieces of $10 notes for $5 notes. The ratio of $5 notes to $10 notes then became 1:2.

How much money did Mr. Tan have?

- VIEW:
- active
- unanswered

- All times are UTC+08:00

It is currently Sun Jun 11, 2023 9:38 am

Powered by phpBB® Forum Software © phpBB Limited

phpBB Metro Theme by PixelGoose Studio