Reduce 180 and 42 to multiples of prime numbers.S-H wrote:Please help the following qtn, thks!

Find the smallest positive integer, n, such that 42n is a multiple of 180

180 = 2 * 2 * 3 * 3 * 5

42 = 2 * 3 * 7

Some numbers must be multipled to 42 in order to become a multiple of 180.

These numbers must include at least one 2, one 3 and one 5, since these are missing from the prime numbers of 42.

The smallest n = 2*3*5 = 30.

Ans: 30