PSLE marks the graduation of Primary school students and their entry into Secondary schools as teenagers. Discuss all issues about Secondary schooling here.
Boys2Men
OrangeBelt Posts: 57
Joined: Fri Nov 21,

Hi there,

I need a private tutor, preferably a male with good experience and credentials to coach my son for A Math ( IP ) who is currently in Year 4.

Kindly pm me.

Thanks.

S-H
BrownBelt Posts: 564
Joined: Mon Feb 08,
Total Likes:1

Hi I can't find where to put this question, this is a sec 2 maths question, can someone kindly help me with this, thank you!

(a) Solve the following inequality:-
4x - 3
------- < 5x + 2
7

(b) Write down the smallest integer that satisfies this inequality

EconsPhDTutor
OrangeBelt Posts: 39
Joined: Sat Jan 23,
Total Likes:1

S-H wrote:Hi I can't find where to put this question, this is a sec 2 maths question, can someone kindly help me with this, thank you!

(a) Solve the following inequality:-
4x - 3
------- < 5x + 2
7

(b) Write down the smallest integer that satisfies this inequality

(4x - 3) ÷ 7 < 5x + 2

⇔ 4x - 3 < 35x + 14

⇔ - 17 < 31x

⇔ - 17 ÷ 31 < x

The solution is x > -17/31.

The smallest integer that satisfies this inequality is 0.

Hope this helps and feel free to ask for any clarifications.

- Dr. Choo Yan Min

www.EconsPhDTutor.com

S-H
BrownBelt Posts: 564
Joined: Mon Feb 08,
Total Likes:1 questionable_i
BrownBelt Posts: 535
Joined: Sat Oct 10,
Total Likes:1

Can anyone help me with this question?
Evaluate 2^x/2^4=2^1/2^(2y-2)

kennethTutor
OrangeBelt Posts: 39
Joined: Mon Jul 13,
Total Likes:2

questionable_i wrote:Can anyone help me with this question?
Evaluate 2^x/2^4=2^1/2^(2y-2)
Applying a^m / a^n = a^(m - n),

2^x/2^4 = 2^1/2^(2y - 2)

2^(x - 4) = 2^(1 - (2y - 2))

2^(x - 4) = 2^(3 - 2y)

Comparing the indices on both sides,

x - 4 = 3 - 2y

x = 7 - 2y

I think this is probably a simultaneous equation question. You need another equation to solve for x and y.

KSP2013777
OrangeBelt Posts: 92
Joined: Fri Dec 28, KSP2013777
OrangeBelt Posts: 92
Joined: Fri Dec 28, kennethTutor
OrangeBelt Posts: 39
Joined: Mon Jul 13,
Total Likes:2 Use the double angle formula: cos 2β = 2 cos^2 β - 1

Make cos β the subject.

Because of the square root, there will be two possible answers (one positive and one negative).

Since 2β and α are in the same quadrant, and sin α is negative and tan 2β is positive, both angles are in the fourth quadrant (between 270° and 360°).

Angle β should be between 135° and 180° (2nd quadrant). Thus we expect cos β to be negative.

Ans should be -√(7/8)

KSP2013777
OrangeBelt Posts: 92
Joined: Fri Dec 28, 