## Q&A - PSLE Math

Academic support for Primary 6 and PSLE
sushi88
KiasuGrandMaster
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### Re: Q&A - PSLE Math

Leah_ wrote:Hi! Need help with this qns. Thanks!

Peter had some \$2 notes and \$5 notes. He spent 50% of the \$2 notes and 3/5 of his \$5 notes. The value of the \$2 notes left was the same as the value of the \$5 notes left. The difference between the value of the \$2 notes and the value of the \$5 notes he had at first was \$45. How much did Peter have at first?

An alternative solution:

<---\$-left----><----\$-spent-------->
---<--50%-->
\$2 (----2u----)(------2u-----)<-45-> <----\$45 is the difference at first
\$5 (--u--)(-u-)(--u--)(--u---)(--u---)
----<-- 2/5--><--------3/5--------->

Hence u-> 45
Peter has 9u at first => 9x45 = \$405

Nickal
YellowBelt
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### Re: Q&A - PSLE Math

Hi, anyone can help? Tks in advance.

The ratio of the number of Larry's marbles to the number of John's marbles was 3:5. In a game with their friends, Larry won 15 marbles while John lost 3 marbles. They both then had the same number of marbles. How many marbles did both boys have altogether before the game?

sushi88
KiasuGrandMaster
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### Re: Q&A - PSLE Math

Nickal wrote:Hi, anyone can help? Tks in advance.

The ratio of the number of Larry's marbles to the number of John's marbles was 3:5. In a game with their friends, Larry won 15 marbles while John lost 3 marbles. They both then had the same number of marbles. How many marbles did both boys have altogether before the game?
Time--------Larry----John
Before--------3u-------5u
After--------3u+15-----5u-3

3u+15=5u-3
2u=18
u=9
Before total is 8u..Hence 8x9=72 marbles

Nickal
YellowBelt
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### Re: Q&A - PSLE Math

That's a great help! Tq!

ninjamathtv
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### Re: Q&A - PSLE Math

Nickal wrote:Hi, anyone can help? Tks in advance.

The ratio of the number of Larry's marbles to the number of John's marbles was 3:5. In a game with their friends, Larry won 15 marbles while John lost 3 marbles. They both then had the same number of marbles. How many marbles did both boys have altogether before the game?
To make this question easier to understand, you can draw bar models like the video below:

Dr.Ta
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### Re: Q&A - PSLE Math

BigDevil wrote:vvv
A: 1696145
Subject: {Math}
Level: {P6}
Tags: {Speed}
Source: {}
^^^
belnanna wrote:

At 24min(o.4hr), Peter reached. meaning dave covered 2km lesser in 0.4hr.

therefore distance between town a n b = 0.4 x 70 + 2=30km

Peter speed = 30/0.4 hr = 75km/h

Ender
BrownBelt
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### Re: Q&A - PSLE Math

Dr.Ta wrote:
BigDevil wrote:vvv
A: 1696145
Subject: {Math}
Level: {P6}
Tags: {Speed}
Source: {}
^^^
belnanna wrote:

At 24min(o.4hr), Peter reached. meaning dave covered 2km lesser in 0.4hr.

therefore distance between town a n b = 0.4 x 70 + 2=30km

Peter speed = 30/0.4 hr = 75km/h
Your solution completely ignore the "6 minutes after they pass each other". If you considered this information, the whole question is flawed.

peggy
BlueBelt
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Joined: Wed Nov 26,

### Re: Q&A - PSLE Math

Kindly assist with this :

At a fun-raising event, 60% of the people were male and the rest were female. 20% of the female left the event in the afternoon.
In the evening, after 33 male and 35 female left the event, 75% of the people at the event were male.
a) What percentage of the people left the event in the afternoon ?
b) How many people were there at the start of the fun raising event ?

Ender
BrownBelt
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Joined: Sat Apr 26,
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### Re: Q&A - PSLE Math

peggy wrote:Kindly assist with this :

At a fun-raising event, 60% of the people were male and the rest were female. 20% of the female left the event in the afternoon.
In the evening, after 33 male and 35 female left the event, 75% of the people at the event were male.
a) What percentage of the people left the event in the afternoon ?
b) How many people were there at the start of the fun raising event ?