## Q&A - P4 Math

### Re: Q&A - P4 Math

Dear Parents

Can anyone help with the following question?

A class has an equal number of boys and girls. Half of the boys and 15 girls do not wear glasses. 12 pupils in the class wear glasses. How many pupils are there in the class?

Thanks in advance.

Can anyone help with the following question?

A class has an equal number of boys and girls. Half of the boys and 15 girls do not wear glasses. 12 pupils in the class wear glasses. How many pupils are there in the class?

Thanks in advance.

- MathIzzzFun
- KiasuGrandMaster
**Posts:**2358**Joined:**Wed Mar 09,**Total Likes:**5

### Re: Q&A - P4 Math

Hirocklee wrote:Dear Parents

Can anyone help with the following question?

A class has an equal number of boys and girls. Half of the boys and 15 girls do not wear glasses. 12 pupils in the class wear glasses. How many pupils are there in the class?

Thanks in advance.

there are equal number of boys and girls. Total number of students = 4u, 1u = half the boys.

so, 3u = 12 + 15 = 27, 1u = 9

Total number of students in the class = 9 x 4 = 36

cheers.

### Re: Q&A - P4 Math

Use the number 1 to 9 to form a three digits number minus a three digit number and the answer is also a three digit number. Each number can only be used once. How many solution can u find? Is there any quick way to get the answer?

- MathIzzzFun
- KiasuGrandMaster
**Posts:**2358**Joined:**Wed Mar 09,**Total Likes:**5

### Re: Q&A - P4 Math

Hello,

I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

- MathIzzzFun
- KiasuGrandMaster
**Posts:**2358**Joined:**Wed Mar 09,**Total Likes:**5

### Re: Q&A - P4 Math

Hiusaik wrote:Hello,

I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9

102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2

So, area of V = 17 x 9 = 153 cm2

V-W= 153 - 36 = 117 cm2

cheers.

### Re: Q&A - P4 Math

Hi MathIzzzFun,MathIzzzFun wrote: Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9

102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2

So, area of V = 17 x 9 = 153 cm2

V-W= 153 - 36 = 117 cm2

cheers.

Thank you for the working!

Regards.

- MathIzzzFun
- KiasuGrandMaster
**Posts:**2358**Joined:**Wed Mar 09,**Total Likes:**5

### Re: Q&A - P4 Math

u r welcomeusaik wrote:Hi MathIzzzFun,MathIzzzFun wrote: Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9

102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2

So, area of V = 17 x 9 = 153 cm2

V-W= 153 - 36 = 117 cm2

cheers.

Thank you for the working!

Regards.

cheers.