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Q&A - P4 Math

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rocklee: GreenBelt; Posts: 111; Joined: Tue May 12,; Total Likes:4

Re: Q&A - P4 Math

Post by rocklee » Mon Sep 05, 2011 4:59 pm

Dear Parents

Can anyone help with the following question?

A class has an equal number of boys and girls. Half of the boys and 15 girls do not wear glasses. 12 pupils in the class wear glasses. How many pupils are there in the class?

Thanks in advance.

MathIzzzFun: KiasuGrandMaster; Posts: 2358; Joined: Wed Mar 09,; Total Likes:5

Re: Q&A - P4 Math

Post by MathIzzzFun » Mon Sep 05, 2011 5:11 pm

rocklee wrote:Dear Parents

Can anyone help with the following question?

A class has an equal number of boys and girls. Half of the boys and 15 girls do not wear glasses. 12 pupils in the class wear glasses. How many pupils are there in the class?

Thanks in advance.

Hi

there are equal number of boys and girls. Total number of students = 4u, 1u = half the boys.

so, 3u = 12 + 15 = 27, 1u = 9

Total number of students in the class = 9 x 4 = 36

cheers.

janicelhl: OrangeBelt; Posts: 64; Joined: Mon Oct 12,

Re: Q&A - P4 Math

Post by janicelhl » Tue Sep 06, 2011 10:49 am

Use the number 1 to 9 to form a three digits number minus a three digit number and the answer is also a three digit number. Each number can only be used once. How many solution can u find? Is there any quick way to get the answer?

rocklee: GreenBelt; Posts: 111; Joined: Tue May 12,; Total Likes:4

Re: Q&A - P4 Math

Post by rocklee » Tue Sep 06, 2011 3:20 pm

Hi MathsIzzzfun

Thanks for your solution.

MathIzzzFun: KiasuGrandMaster; Posts: 2358; Joined: Wed Mar 09,; Total Likes:5

Re: Q&A - P4 Math

Post by MathIzzzFun » Tue Sep 06, 2011 4:14 pm

rocklee wrote:Hi MathsIzzzfun

Thanks for your solution.

u r welcome

cheers.

usaik: BlueBelt; Posts: 269; Joined: Sat Jul 19,; Total Likes:1

Re: Q&A - P4 Math

Post by usaik » Sat Sep 10, 2011 5:35 pm

Hello,
I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

MathIzzzFun: KiasuGrandMaster; Posts: 2358; Joined: Wed Mar 09,; Total Likes:5

Re: Q&A - P4 Math

Post by MathIzzzFun » Sat Sep 10, 2011 6:52 pm

usaik wrote:Hello,
I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
So, area of V = 17 x 9 = 153 cm2
V-W= 153 - 36 = 117 cm2

cheers.

chokos: YellowBelt; Posts: 12; Joined: Wed Apr 28,

Re: Q&A - P4 Math

Post by chokos » Sun Sep 11, 2011 9:23 pm

@ Tianzhu
Thank you very much.

usaik: BlueBelt; Posts: 269; Joined: Sat Jul 19,; Total Likes:1

Re: Q&A - P4 Math

Post by usaik » Mon Sep 12, 2011 5:17 am

MathIzzzFun wrote: Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
So, area of V = 17 x 9 = 153 cm2
V-W= 153 - 36 = 117 cm2

cheers.

Hi MathIzzzFun,
Thank you for the working!
Regards.

MathIzzzFun: KiasuGrandMaster; Posts: 2358; Joined: Wed Mar 09,; Total Likes:5

Re: Q&A - P4 Math

Post by MathIzzzFun » Mon Sep 12, 2011 6:11 am

usaik wrote:
MathIzzzFun wrote: Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
So, area of V = 17 x 9 = 153 cm2
V-W= 153 - 36 = 117 cm2

cheers.
Hi MathIzzzFun,
Thank you for the working!
Regards.

u r welcome

cheers.

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