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Q&A - PSLE Math

Academic support for Primary 6 and PSLE
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taringal
KiasuNewbie
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Posts: 8
Joined: Tue Aug 03,

Re: Q&A - PSLE Math

Post by taringal » Sun Apr 17, 2016 11:53 am

Hi,

Please help on this question. Thank you.

Patrick, Devi and Jiamin each have the same number of beads. How many beads must Devi give to Patrick and Jiamin so that Patrick has 20 beads more than Devi and Jiamin has 4 fewer beads than Patrick?
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numeric
GreenBelt
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Posts: 163
Joined: Wed Feb 16,
Total Likes:9

Re: Q&A - PSLE Math

Post by numeric » Sun Apr 17, 2016 11:29 pm

taringal wrote:Hi,

Please help on this question. Thank you.

Patrick, Devi and Jiamin each have the same number of beads. How many beads must Devi give to Patrick and Jiamin so that Patrick has 20 beads more than Devi and Jiamin has 4 fewer beads than Patrick?
Image
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S-H
BrownBelt
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Posts: 564
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Total Likes:2

Re: Q&A - PSLE Math

Post by S-H » Fri Apr 22, 2016 11:09 pm

Please help the following qtn, thks!
Find the smallest positive integer, n, such that 42n is a multiple of 180
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Jmaths.SG
YellowBelt
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Posts: 19
Joined: Fri Apr 01,

Re: Q&A - PSLE Math

Post by Jmaths.SG » Sat Apr 23, 2016 12:11 am

S-H wrote:Please help the following qtn, thks!
Find the smallest positive integer, n, such that 42n is a multiple of 180
Reduce 180 and 42 to multiples of prime numbers.
180 = 2 * 2 * 3 * 3 * 5
42 = 2 * 3 * 7

Some numbers must be multipled to 42 in order to become a multiple of 180.
These numbers must include at least one 2, one 3 and one 5, since these are missing from the prime numbers of 42.

The smallest n = 2*3*5 = 30.

Ans: 30
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S-H
BrownBelt
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Posts: 564
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Re: Q&A - PSLE Math

Post by S-H » Sat Apr 23, 2016 8:46 am

Jmaths.SG wrote:
S-H wrote:Please help the following qtn, thks!
Find the smallest positive integer, n, such that 42n is a multiple of 180
Reduce 180 and 42 to multiples of prime numbers.
180 = 2 * 2 * 3 * 3 * 5
42 = 2 * 3 * 7

Some numbers must be multipled to 42 in order to become a multiple of 180.
These numbers must include at least one 2, one 3 and one 5, since these are missing from the prime numbers of 42.

The smallest n = 2*3*5 = 30.

Ans: 30
Understand, thank you very much!
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S-H
BrownBelt
BrownBelt
Posts: 564
Joined: Mon Feb 08,
Total Likes:2

Re: Q&A - PSLE Math

Post by S-H » Sat Apr 23, 2016 9:00 am

Can someone pls help, thanks!

(a) Solve the following inequality
4x-3
------- less than. 5x+2
7

(b) write down the smallest integer that satisfies this inequality
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SAHMom
OrangeBelt
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Posts: 60
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Re: Q&A - PSLE Math

Post by SAHMom » Sat Apr 23, 2016 2:35 pm

taringal wrote:Hi,

Please help on this question. Thank you.

Patrick, Devi and Jiamin each have the same number of beads. How many beads must Devi give to Patrick and Jiamin so that Patrick has 20 beads more than Devi and Jiamin has 4 fewer beads than Patrick?
Hi, hope the below helps...
Image
Top

S-H
BrownBelt
BrownBelt
Posts: 564
Joined: Mon Feb 08,
Total Likes:2

Re: Q&A - PSLE Math

Post by S-H » Sat Apr 23, 2016 10:49 pm

Hi, can someone pls help, thks!

(a) solve the following inequality

4x-3
---------- < 5x + 2
7

(b) write down the smallest integer that satisfies this inequality
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ozora
BlueBelt
BlueBelt
Posts: 326
Joined: Thu Feb 24,

Re: Q&A - PSLE Math

Post by ozora » Sun Apr 24, 2016 10:42 am

Need some guide on the following questions.
Thanks
Image
Image
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MathWithModels
YellowBelt
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Posts: 11
Joined: Sun Dec 28,

Re: Q&A - PSLE Math

Post by MathWithModels » Mon Apr 25, 2016 9:37 am

Question:

Catherine had some money at first. She gave 1/4 of her money to
Anne. As a result, Anne had thrice as much as before. Then, Anne
gave 1/2 of her money to Bernard. Bernard then had 1 1/2 times as
much money as before. Anne still had $129 left. How much money
did each child have at first?

Answer:

Anne

We work backwards for Anne. She had $129 at the end.
This was after giving half her money to Bernard. So, she gave $129 to Bernard.
Before giving $129 to Bernard, she had $129 + $129 = $258.
Anne tripled her money after getting 1/4 of Catherine's money.
So Anne had $258/3 = $86 at first.

Anne had $86 at first

Catherine

Anne tripled her money after getting 1/4 of Catherine's money.
As Anne had $86 at first, she received 2 x $86 = $172 from Catherine.
This was 1/4 of Catherine's money
So Catherine had $172 x 4 = $688 at first

Catherine had $172 x 4 = $688 at first

Bernard

Bernard received $129 from Anne, and had 1 1/2 times as much as before.
So the $129 was half what he had at first.
So Bernard had $129 x 2 = $258 at first.

Bernard had $129 x 2 = $258 at first
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