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Just trying… dunno whether right or not…

a) Angle B’CA’ = 62

So Angle BCA’ = 180 – 62 – 62 = 56

b) I assume they are asking for the height of triangle B’CA’.

So sin 62 = h/6

Therefore h = 6 * sin 62 = 5.298 = 5.30 cm

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also may i ask why did u use sin? 6cm isn’t a hypotenuse 

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I measured the vertical height from A’ straight down to the floor.  Let’s call the point on the floor to be P.  So for triangle A’CP, we have sin 62 = A’P/A’C.

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Ohhh thank you!! 😩😋

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BCA = 180-62-62 = 56

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