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$3600 translates to 360 pieces of $10 notes
H    :    J
2    :    3
-360    +360
1    :    6

2u – 360 = 1p —(1)
3u + 360 = 6p –(2)

(1) X 6,
12u – 2160 = 6p

3u +360 = 12u -2160
9u = 2520
u = 280

2u -360 = p
p = 560-360 = 200

In the end, H has 1p = 200 pieces of $10, =>value = $2000
J has 3u of $2notes=> 840 notes, Value = $1680.
Total J has in the end = 1680 + 3600 = $5280
The difference between what they left = $5280 – $2000 = $3280 ###

 
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