Can anyone please help on these questions please, thanks.

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# Question

# Answer

9.

(1) A = 4O

(2) 2P = A

Since P = 192, from (2), we get

2(192) = A

=> A = 384

Substituting into (1), we get

(384)/4 = O

=> O = 96

So he bought 384 – 96 = **288 #** more apples than oranges.

Q9: the answer is wrong.

Apple = 4 units

Orange = 1 unit

Pears = 4×2 = 8units

8 units = 192

1 unit = 192/8 =24

3 units = 24×3 = 72 more apples

(1) A = 4O

(2) P = 2A (This should have been the equation… so sorry)

Since P = 192, from (2), we get

192/2 = A

=> A = 96

Substituting into (1), we get

(96)/4 = O

=> O = 24

So he bought 96 – 24 = **72 #** more apples than oranges.

11.

(1) A + J = 220

A – 38 = 5 (J – 38)

=> (2) A = 5J – 190 + 38 = 5J – 152

Substituting (2) into (1), we get

5J – 152 + J = 220

6J – 152 = 220

6J = 372

J = **62 #**

10.

A + B + C = 2650

A + (A – 76) + (A – 76)/4 = 2650

9/4A – 76 – 76/4 = 2650

9/4A – 95 = 2650

9/4A = 2745

A = 1220

So B has 1220 – 76 = **1144 # stickers**

8.

R = 288

3(B + G) = 288

3(57 + G) = 288

171 + 3G = 288

3G = 117

=> G = 39

So Marc has 288-39 = **249 #** more red than green marbles.

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