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Area of ABCD = 98cm² 
Now, AC = ✓(AB² + BC²) = ✓2AB² =  ✓(2×98) = 14cm

a) Since AC = WX,
Perimeter of WXYZ = 4×14 = 56 #

b) Area of circle = 3.14 x (14/2)² = 153.86cm² 
Therefore area of shaded parts = 153.86 – 98 = 55.86cm² #

1 Reply 1 Like

P6 no learn pythagoras theorem leh

btw ABCD area is 95 or 98

 

1 Reply 0 Likes

Is it?  No Pythagoras Theorem?  Oops.

0 Replies 0 Likes

this way we can also find area of bigger square as well , in case they ask

 

PS: given area i assume is 98

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