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Question

GCE O-Level Mathematics

Question post on Wed, 04/05/2022 11:30am

Thank you.

Answer

sushi88 Post on Wed, 04/05/2022 12:50pm

(b) When t = 5, D = 42

D = kt² where k is a constant.

k = D/t² = 42 / 25 = 1.68

Therefore equation is D = 1.68t²

(c) When D = 30,

1.68t² = 30

t² = 30/1.68 => t = 4.23 s

sushi88

Post on Wed, 04/05/2022 12:50pm

(b) When t = 5, D = 42

D = kt² where k is a constant.

k = D/t² = 42 / 25 = 1.68

Therefore equation is D = 1.68t²

(c) When D = 30,

1.68t² = 30

t² = 30/1.68 => t = 4.23 s

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