James bought 161 more red balls than blue balls. After selling 6/7 of the red balls and half of the blue balls, he had 113 balls left. How many balls did he sell?
STUCK ON HOMEWORK?
ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!
Question
Answer
ChiefKiasu
Thanks! Here’s my attempt using simultaneous equations.
R – B = 161 …(1)
(1/7)R + (1/2)B = 113
R + (7/2)B = 113*7
R + (7/2)B = 791 …(2)
(2) – (1):
(9/2)B = 630
B = 140
So, R = 301
Total balls sold = 140 + 301 – 113 = 328 #
sushi88
R [ —–u———][161]
B [——u———]
After selling 6/7 Red balls and 1/2 Blue balls,
1/7 (u +161 ) + (1/2)u = 113
2(u+161) + 7u = 113 x 14 = 1582
9u + 322 = 1582 => u = 1260/9 = 140
Total balls sold = 2 x 140 + 161 – 113 = 328
narendiran
Thanks for the answer.
ChiefKiasu
Thanks! Here’s my attempt using simultaneous equations.
R – B = 161 …(1)
(1/7)R + (1/2)B = 113
R + (7/2)B = 113*7
R + (7/2)B = 791 …(2)
(2) – (1):
(9/2)B = 630
B = 140
So, R = 301
Total balls sold = 140 + 301 – 113 = 328 #