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P6 Mathematics

Question post on Sun, 22/05/2022 6:45pm

An Express train left town A for town B at the same time a normal train travelling from the opposite direction left town B for town A. The average speed of the express train 120 km/h more than that of the normal train. The express train and the normal train took 6 hrs and 10 hrs to reach their destination respectively.

a) Find the average speed of the express train?

b) Find the distance between Town A and Town B?

Answer

sushi88 · Answer 1 · Post on Sun, 22/05/2022 10:56pm

Speed Time Distance

Express [u][120] 6 D (Town A to Town B)

Normal [u] 10 D (Town B to Town A)

Distance/Speed = Time

D/u = 10 => D = 10u

D/(u+120) = 6

=> 10u/(u+120) = 6

=> 10u- 6u = 720 Therefore, u = 720/4 = 180

(a) Average speed of Express Train = u+120 = 180+120 = 300km/h

(b) Distance between Town A and Town B = 10u = 10 x 180 = 1800km