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The figure is something wrong.   If the triangle is a right angle, the side and hypothenuse cannot be equal, i.e. 12 cm.    The hypothenuse is the longest side in a right-angle triangle.  If they are equal, it would be an isosceles triangle.

Ok I got the diagram now.

Both 12 x 12 papers are folded and joined at the folded part.

So the figure should be  (144-24) x 2 = 240 cm2

Your working only minus “area of one right-angle triangle” when it should be two because both papers are folded, then they can join….otherwise the side 12 cm and hypothenuse(longer than 12 cm) cannot join properly.

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