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Before :   Total = 7u   at first

50cts coins    [  u   ][   u   ] 

$1 coins          [  u   ][   u   ][  u   ][   u   ][  u   ]

After:

50cts coins    [  u   ][   u   ] [ 10]   <—————————-5/0.50 =10 coins

$1 coins          [  u   ][   u   ][  u   ][   u   ][  u   ][  10] <——- Mum gave 10 coins

                         <—  2 times of 50cts coins—->

So,   2(2u+10) = 5u+10

4u + 20 = 5u + 10

u = 20-10 = 10

Hence Owen has 7×10 =70 coins at first

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