Alternative Solution:

Chocolate     [u][24][36]

Almond        [u][24]

Butter           [u]

(3/4) (u+60) + (1/3)(u+24) + (1/6)(u) = 323        <—— x 12 on both sides

9u + 540 + 4u + 96 + 2u = 3876

15u = 3240

u = 216

Hence number of chocolate cookies made by Megan = u + 60 = 216 + 60 = 276

Thanks!  Not very sure about using models at all (my brain is all shot).  Needs time to digest 🙂

C – A = 36 … (1)

A – B = 24 … (2)

(1/3)A + (1/6)B + (3/4)C = 323
A + (1/2)B + (9/4)C = 969 … (3)

(1) + (2):
C – B = 36 + 24 = 60 … (4)

(3) – (2):
(3/2)B + (9/4)C = 969 – 24 = 945
B + (2/3)(9/4)C = (2/3)945
B + (3/2)C = 630 … (5)

(4) + (5):
(5/2)C = 630 + 60 = 690
C = (2/5)690 = 276 #

PS. This is a crazy sum that requires 5 simultaneous equations!

Chief, 

You did well but some kids would trip to do so many simultaneous equations…hence model diagram was introduced.   Having said this, some questions are difficult to solve by using model diagrams while using algebra with simultaneous equations are actually better.  So got to assess the situation.