
appreciate some assistance to solve the question
appreciate some assistance to solve the question
(a) Assume the length of the wooden block is L and the width is W
Volume of block before reduction = 14LW
Length of block after reduction = (3/5) L
Breadth of block after reduction = (3/4)W
Volume of block after reduction = (3/5)L x (3/4) W x 14 = [ (9 x 14) /20 ] LW
Hence fraction final volume of the block against the original volume
= [ ( 9 x 14) /20 ] LW
——————–
14 LW
= 9/20
(b) 9u -> 819 => u = 91 Hence 20u = 1820
Let BA = base area of the original block
BA x height = 1820
BA x 14 = 1820
BA = 1820 / 14 = 130
Hence base area of the original block = 130cm2
PS : Please click on “Accept Answer” if the answer is correct.
thanks
a.
Original volume of block = 14LW
Area of block after reduction = (3/5) L * (3/4) W = (9/20)LW
Volume of block after reduction = (9/20)LW * 14 =(63/10)LW = 6.3LW
So fraction of original volume = 6.3/14 = 0.45 #
b. 6.3LW = 819 cm3
LW = 130 cm2 #