Thank you.the top question did I get correct.thanks.the second question is a bit confused.thanks.

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Question 10:

<——————180km———————–>

X |<—————–|——————————->| Y

Lorry(9:30) 11:00 Car(9:30)

Speed of car = u

Speed of lorry = u-30

11:00-9:30 = (3/2)h Using distance = speed x time,

(3/2)u + 3/2 (u-30) = 180 <——– x 2 on both sides

3u + 3u – 90 = 360

6u = 450 => u = 75

Hence speed of car is 75km/h

PS: Please click ” Accept Answer” if the answer is correct.

Question 9:

Your working is partially correct. You start getting wrong when you add speed to distance. They cannot be added together.

P |——————————-|—————-|———————>| Q

H<—- 12 –>A<——- u———>

A = 80km/h after (3/4) h, Distance travelled by A = 80 x (3/4) = 60

H = 64km/h after (3/4) h, Distance travelled by H = 64 x (3/4) = 48

Distance between them after 45 mins = 60 – 48 = 12

Let u be the distance of A’s remaining journey to Q

Time taken by A to complete remaining journey = u/80

H increases speed to 86km/h for the remaining journey

Remaining journey of H = 12 + u

Time taken by H to complete remaining journey = (12+u)/86

They arrived at the same time at Q,

u/80 = (12+u)/86

86u = 80u + 960

6u = 960 => u = 160

Hence the distance between town P and Q = 60+160 or 48+12+160 = 220km

PS: Please click ” Accept Answer” if the answer is correct.

Hi Prettyhomework,

If the answer is incorrect, please provide the answer key so that corrections can be made.

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