Is my steps correct?thank you.

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Your steps are incorrect. Also, remember never write statements like this:

180-80** =** 100/2 as they are **NOT EQUAL**. It is a common mistake students make to save time by combining 2 mathematical statements into one. It should be 180-80 = 100, then 100/2 = 50 or (180-80)/2 = 50 if you want to combine steps.

**Solution:**

(a) Since AEB is an equilateral triangle, AE = AB = EB

and since EBCD is a rhombus, EB = BC = CD = DE

Angle EBC = Angle EDC = 80 (Opp angles inside a rhombus)

Angle ABE = 60 (Angles inside equilateral triangle)

Angle ABC = 60 + 80 = 140

Hence Angle BAC = (180-140) / 2 = 20^{0} (angles in an isosceles triangle, AB=BC)

(b) Angle BEC = (180-80)/2 = 100 (angles in an isosceles triangle, EB = BC)

Angle AEB = 60 (Angles inside equilateral triangle)

Hence Angle AEC = 60 + 100 = 160^{0}

*PS: I present the solution comprehensively for your understanding how to derive the answer. However once you have mastered it, the solution for (a) can be shortened to this:*

*(a) Angle EBC = Angle EDC = 80, Angle ABE = 60*

*Angle ABC = 60 + 80 = 140 *

*Hence Angle BAC = (180-140) / 2 = 20 ^{0}*

Hi just wanted to check, 180-80/2 is actually equal to 50 not 100?

180-80/2 is neither 50 nor 100

180 – 80/2 = 180 – 40 = 140

(180-80) / 2 = 100/2 = 50

Hope this clarifies.