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Question

For this question, is there any methods to solve as this method is very complicated.pls help thanks.

Answer

F = (k/d2 )

Increase in distance by 20% => d =12/10    => New Force = (k/d2 )(10/12)2

ΔF  = Original force – New force

       = (k/d2 ) – (k/d2 )(10/12)2 

        =(k/d2 ) [ 1 – 100/144]

        = 44/144  (k/d2 )

Hence % reduction in Force =  44/144 x 100% = 30.6%  (correct to 3sf)

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