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Question

Answer

a. Total time taken by the bus = 12 – 7:30 = 4.5 hrs
Distance between P and Q = Speed * Time taken = 60 * 4.5 = 270km
b. Total time taken by the car = 10:45 – 7:45 = 3 hrs
Speed of the car = Distance / Time taken = 270 / 3 = 90 km/h
c. At 10:30am,
Distance of car from Q = Speed * Time taken = 90 * 2:45 = 180 + 45/60 *90 = 247.5 km
Distance of bus from P = Speed * Time taken = 60 * 3 = 180 km
So distance between car and bus =

(a) Bus speed = 60
Bus time 7:30-12:00 = 4.5
Hence distance PQ = 60 x 4.5 = 270km
(b) Car total time 7:45 – 1:45 = 3
Car total distance = 270
Hence Car average speed = 270/3 = 90km/h
(c) Bus Time 7:30-10:30 = 3
Bus speed = 60
Bus distance travelled = 60 x 3 = 180 Bus remaining distance = 270-180 = 90
Car Time 7:45-10:30 = 2.75
Car speed = 90
Car distance travelled = 90 x 2.75 = 247.5 Car remaining distance = 270 – 247.5 = 22.5
Hence distance between bus and car at 10:30 = 270 – 90 – 22.5 = 157.5km