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 N = k/ sqrt(t)  where t > 0 and k = constant

N2  = k2 / t 

=> t = (k/N)2

old temperature = (k /N )2  = k2 / N2

new temperature = (k/2N)2  = k2 / 4N2    (when N is doubled)

Δt =  new temperature – old temperature  

     =   (   k2 / 4N2 –  k2 / N2

     =   ( k – 4k2 ) / 4N2 

     = – 3/4  (k/N)2                                                 

Since it is negative, it is a reduction and converting to % = 3/4 x 100% = 75%

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