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# Question

# Answer

(a) Let the point on the ground below point A be O

so AO is the height of the water level before it overflows.

AO/x = sin 30

AO = (1/2)x cm

Hence height of water level just before it overflows is (1/2) x cm

(b) Triangle AFB is the base area of the water volume and height is x

AF/x = 2 cos 30 = 2 (√3/2) = √3

So AF = (√3)x

Area of AFB = (1/2)(√3 (x))(1/2)x = (√3/4) x^{2}

Volume of water = (√3/4) x^{2 } (x) = (√3/4) x^{3}

x^{3} —-> 60s

(√3/4) x^{3 } —–> 60 x (√3/4) = 25.98 ~ 26 seconds to the nearest seconds.

Hence time taken to fill the water to the height in (a) is ~ 26 seconds.

(a) Make point O the point on the ground beneath point A.

Consequently, AO represents the height of the water before it overflows.

A = 30 sin AO/x

AO = (1/2)x cm

The water level is therefore (1/2) x cm high immediately before it overflows. basketball stars

That’s fast!

Thank you very much, Ivory Morissette. word wipe

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