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   Mr Chong  ——> 80km/h

      Bedok                                                                                                           KL

          |<———————–360-u——————————->|<————–u————–>|

        9am                                                                       Meeting pt                 9am

                                                                                         70km/h <————Mr Ma

Let the distance travelled by Mr Ma be u

Then distance travelled by Mr Chong  = 360-u    (the point they met and passed ea is the pink line)

Time taken to reach that point was the same for both of them,

(360-u)/80 = u/70

80u = 25200 – 70u

150u = 25200

u = 168              360-168 = 192

Time taken to reach meeting/crossover point = 168/70       or    192/80

                                                                                    = 2.4 h = 2 hours 24 mins

        |——1h——-|——1h-——|–24m–|

     9am            10am           11am      11:24am

Hence the time they met and passed each other was  11:24am 

PS:  Did you understand the solution for the last 3 questions you posted yesterday in 2 posts?

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Thank you very much. Yes,I am trying to redo again to remember the steps.but sometimes I may get confuse again.thank you very much for your help.

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It is great that you try to understand and practise again.   

Always remember when tired, please take a break.   You can only do Math when the mind has had a good rest.   So just before the exams, sleep well.

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