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Question

Farmer Lee had 200 more chickens than Farmer Wong at first. Farmer Lee sold 40% of his chickens to Farmer Wong. Farmer Wong in return sold 20% of his chickens to
Farmer Lee. In the end, Farmer Wong had 24 chickens more than Farmer Lee How
many chickens did Farmer Lee have at first?

Hi, 

Need assistance for this qns…

Thank you in advance

Regards,

Adm

Answer

                                                Lee                             Wong

At first                                   u+200                              u

Lee sold Wong              -0.4(u+200)               +0.4(u+200)    (when Lee sold 40% of his chix to Wong)

                                      —————–             ——————-

Updated chix                     0.6u+120                     1.4u+80

Wong sold Lee              +0.2(1.4u+80)           -0.2(1.4u+80)   (When Wong sold 20% of his chix to Lee)

                                     ——————-          ——————–

In the end                     0.88u + 136                  1.12u + 64

Wong has 24 more chickens than Lee, so to make them equal, add 24 to Lee’s numbers

1.12u + 64 = 0.88u + 136 + 24

0.24u = 96

u = 400

Hence at first Lee has 400+200 = 600 chickens.

1 Reply 1 Like

hi, Lee at first is 200 more

so why is not U+200 instead of U+20?

1 Reply 0 Likes

Thank you, saw the number short of 1 zero…  amended already. 

0 Replies 0 Likes
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