Lily had 2 boxes of biscuits
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Question
Answer
Box A Box B
At first u + 60 u
A gave 1/4 to B -(1/4)(u+60) +(1/4)(u+60)
Balance (3/4)u +45 (5/4)u + 15
B gave 2/5 to A +(2/5)[(5/4)u + 15] -(2/5)[(5/4)u + 15]
Final balance (5/4)u + 51 (3/4)u + 9
We know at the end A = 2B, so
(5/4)u + 51 = 2 [ (3/4)u + 9 ]
(5/4)u + 51 = (6/4)u + 18
(1/4)u = 33
u = 132
Box A Box B
At first 132 + 60 =192 132
A gave 1/4 to B – 48 +48
Balance 144 180
B gave 2/5 to A 72 -72
Final balance 216 108
(a) Number of biscuits in Box A at first is 192
(b) Difference between biscuits in Box B at first and in the end = 132 -108 = 24