Assuming the child does not know speed syllabus (hence no formulas) since it is covered in P6 only.

Alternative approach:

First hour distance travelled = 86m

Second hour distance travelled = (86/125)   x 100 = 68.8m

Third hour:  1 hour –>  120m  => 20 mins —> (120/60)  x 20 = 40m

Total distance travelled = 86 + 68.8 + 40 = 194.8m

Thank you .

How is this a P3 question? 🙂

1st hour = 86m
2nd hour = 86/1.25  (because 25% farther in 1st hour)
         = 68.8m
3rd hour = speed x time = 120m/h x (20/60)h = 40m
Total distance flew in 3 hours = 96 68.8 + 40 = 194.8m

Thank you