Samantha had some apples in her shop at first.She sold 1/6 of them in the afternoon and 280 of the apples in the evening.She was left with 3/5 of the apples she had at first.She packed these remaining apples into a small and large boxes.Each of the small boxes contained 8 apples while each of the large boxes contained 12 apples
a)How many apples were packed into the boxes
b)Samantha packed 20 more small boxes than large boxes.How many small boxes did she pack?
How to tackle this question?
a)
If Samantha had 30U of apples initially, she sold 5U in the morning and 280 in the evening and left with 30U*3/5=18U
12U=5U+280
U=40
So he packed 18*40=720 apples into the boxes
b)
If she packed L large box, then
12L+ 8*(20+L) = 720
20L=720-160=560
L=28
So he packed 28+20=48 small boxes
sushi88
(a) Apples
Sold 1/6 = 5/30
Left 3/5 = 18 /30
So total apples = 30u, apples sold in the evening = 30u-5u-18u = 7u
7u = 280 => u = 40
Apples left to pack into boxes = 18u = 18 x 40 = 720
(b) Let p be number of small boxes, large boxes = p-20
8p + 12(p-20) = 720
8p+12p = 720 + 240
20p = 960
p = 48
Hence number of small boxes packed was 48.
ChiefKiasu
a.
Let A be the number of apples Samantha had at first.
(1/6)A + 280 = (2/5)A
(2/5)A – (1/6)A = 280
((12 – 5)/30)A = 280
(7/30)A = 280
A = (30/7)280 = 1200
So she had (3/5)1200 = 720 apples packed into boxes #
b.
Let S be the number of small boxes.
Let L be the number of large boxes.
8S + 12L = 720 … (1)
S – L = 20 … (2)
(2) x 8:
8S – 8L = 160 … (3)
(1) – (3):
20L = 560
L = 28
So S = 20 + 28 = 48 #
