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Question

Answer

Total people on bus before the 6 get on = 33-6 = 27
Fraction of people who got off = 2/5 + (1/10)(3/5) = 23/50 [(1/10)=10%]
Remaining fraction of people on bus = 1- (23/50) = 27/50
Since 27/50 —> 27, 50/50=1 —> 27 x (50/27) x 1 = 50
Hence the original number of people on the bus was 50

Let N be the number of people on the bus originally.
90/100(3/5N) + 6 = 33
(270/500)N = 27
So N = (500/270)27 = 50 #

Working: Suppose there are N people. 1st stop: 3/5 N onboard (because 2/5 N got off) 2nd stop: 9/10 x 3/5 N + 6 (because 10% of 3/5 N got off and 6 boarded) So 27/50 N + 6 = 33. That means N = (33-6) x 50/27 = 50. There were 50 people on the bus initially. Checking: start 50 stop1 30 (because 2/5 x 50 = 20 got off) stop2 27 + 6 = 33 (because 10% x 30 = 3 got off, hence 27; 6 more got on)