
C
hi, need help with this maths problem. Thank you!
C
hi, need help with this maths problem. Thank you!
Standing Broad Jump Shuttle Run
Queuing At first 7u 4u
18 from SBJ to SR -18 +18
Then the queues are equal, this implies
7u-18 = 4u+18
3u = 36
u =12
Hence queuing at SBJ was 7u = 84 and queuing at SR was 4u = 48
At the end, both stations have (84+48) = 132 pupils with each 66 pupils.
Thinking:
Ratio is Jump:Run = 7:4. So we can use 7u:4u, a total of 11u.
After some movement they become equal, i.e. divisible by 2.
But 11 is not divisible by 2, so let's scale up by 2 instead.
We use Jump:Run = 14u:8u with a total of 22u (so 22u/2 = 11u).
Working:
JUMP RUN
BEFORE 14u 8u (total of 22u students)
AFTER 11u 11u (3u students moved)
So 3u = 18 and u = 6.
Thus at the start, there are 14 x 6 = 84 students in standing
board jump queue and 8 x 6 = 48 students in shuttle run queue.
At the end, there are 66 students in both queues.
Checking:
JUMP RUN BEFORE 84 48 AFTER 66=84-18 66=48+18 (18 students moved)
Regarding the working you cancelled out, it can also be made to work: JUMP RUN BEFORE 7u 4u AFTER 7u-18 4u+18 They are equal at the end, so 7u-18=4u+18 => 3u=36 => u=12. It gives the same answer: JUMP RUN BEFORE 7x12=84 4x12=48 AFTER 84-18=66 48+18=66